What is 2x-6y=12 how do you solve this

How do I solve this?

ra1l [238]

Answer:

(-6,1) (2,7)

Step-by-step explanation:

y =x+5

y = x^2 +5x-7

Set the two equations equal since y=y

x+5 = x^2 +5x -7

Subtract x from each side

x-x+5 = x^2 +5x-x -7

5 = x^2 +4x -7

Subtract 5 from each side

5-5 = x^2 +4x -7-5

0 = x^2 +4x-12

Now we can factor the right side

What 2 numbers multiply to -12 and add to +4

6*-2 =-12

6-2 =4

0 = (x+6) (x-2)

Using the zero product property

x+6=0 x-2=0

x=-6 x=2

We need to find y for each value of x

y = x+5 y = x+5

y = -6+5 y = 2+5

y =1 y = 7

4 0

2 years ago

A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe

ycow [4]

Missing part of the question

Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)

Answer:

$S_n = \frac{n}{2}(n - 1)$

Step-by-step explanation:

Given

For 5 people

$\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}$

Using the given instance of 5 people, the number of handshakes can be represented as:

$(n - 1) + (n - 2) + (n - 3) + ........ + 3 + 2 + 1 + 0$

The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

$S_n = \frac{n}{2}{(T_1 + T_n})$

Where

$T_1 = n - 1$ --- The first term

$T_n = 0$ --- The last term

So:

$S_n = \frac{n}{2}(n - 1 + 0)$

$S_n = \frac{n}{2}(n - 1)$

7 0

2 years ago

(3x8)x4=3x what is the answer

RUDIKE [14]

X=32 is your answer

6 0

2 years ago

Read 2 more answers

How does this polynomial identity work on numerical relationships? (y + x) (ax + b)

Serggg [28]

Let us take 'a' in the place of 'y' so the equation becomes

(y+x) (ax+b)

Step-by-step explanation:

Step 1:

(a + x) (ax + b)

Step 2: Proof

Checking polynomial identity.

(ax+b )(x+a) = FOIL

(ax+b)(x+a)

ax^2+a^2x is the First Term in the FOIL

ax^2 + a^2x + bx + ab

(ax+b)(x+a)+bx+ab is the Second Term in the FOIL

Add both expressions together from First and Second Term

= ax^2 + a^2x + bx + ab

Step 3: Proof

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

Identity is Found .

Trying with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)

((10)+8)(7) =(2*25)+(4*5)+(40)+(16)

(18)(7) =(50)+(20)+(56)

126 =126

3 0

3 years ago

an item that cost $50 is marked 20% off. Sales tax for the item is 8%. What is the final price including tax? Solve the problem

kramer

Answer:

$43.20

Step-by-step explanation:

The price with tax is 100% + 8% = 1.08 times the price before tax. The discount multplies that price by 100% -20% = 0.80. The discount multiplier is the same whether the discount is applied before or after the tax.

The combined effect of the two multipliers is ...

... 1.08 × 0.80 = 0.864

so the discounted price with tax added is 0.864 × $50 = $43.20

_____

Perhaps you're supposed to figure the tax (8% of $50 = $4), add the tax ($50 +4 = $54), then subtract the discount (20% of $54 = $10.80) to get

$54.00 -10.80 = $43.20

6 0

3 years ago