this just wants us to calculate 4/5-1/3
make common denom
4/5 times 3/3=12/15
1/3 times 5/5=5/15
4/5-1/3=12/15-5/15=(12-5)/15=7/15
7/15lb is left
To find the maximum height you need to find the vertex:(h,k)
Your equation is in vertex form a(x-h)+k and the vertex is (h,k) where k is the maximum height and the h is the distance it went to reach the maximum height.
k=6 so the kangaroo's maximum height is 6 feet.
To find how long is the kangaroo's jump, take a look at the graph. You will notice that the parabola ends at the distance the kangaroo jumped. You will also see that it is the one of the x-intercepts.
-.03(x-14)^2+6=0
-.03(x-14)^2+6-6=0-6
-.03(x-14)^2=-6
-.03/-.03(x-14)=-6/-.03
(x-14)^2=200
[(x-14)^2]^.5=200^.5
x-14=(200)^.5
x-14+14=(200)^.5+14
x≈28.14 feet
The kangaroo jumped a distance of 28.14 feet.
You will notice that the square root of a number gives you two solutions a positive and a negative one. The other solution is -.14, which we know distance is not negative so we do not use that solution. Also, I used the ^.5 instead of using the square root. It is the same.
Answer: 99 cent store
Step-by-step explanation:
Answer:
-147
Step-by-step explanation:
-8 x 25 + 60 -7
Answer:
x^2 + y^2 = 12
Step-by-step explanation:
For a circle with the center at the origin [(h,k) is (0,0)]
use the formula:
x^2 + y^2 = r^2
In this case r is 2sqroot3.
(2sqroot3)^2 is 12.
2•2•sqrt3•sqrt3
= 4•3
= 12
So we get,
x^2 + y^2 = 12
