Ask question

Ask question

All categories

2 years ago

12

–3x + 1 + 10x = x + 4

2 answers:

Anvisha [2.4K]2 years ago

4 0

Alright so I will solve and explain as I go :)

First, let's combine like terms.

-3x + 1 + 10x = x + 4
7x + 1 = x + 4

Now, subtract the one from the left. (we do this to combine terms)

7x + 1 = x+ 4
7x = x + 3

Now subtract the x from the right. (this is also to combine terms)

7x = x + 3
6x = 3

Finally, divide by 6 on both sides.

6x = 3
x = 1/2 or 0.5

Hope this helps!

SSSSS [86.1K]2 years ago

3 0

-3x+1+10x=x+4
1+7x=x+4
6x=3
x=.5

You might be interested in

The price of a new 4G-cell phone is $200 in store A and $240 in store B. If you get 15% discount in store B, where would you buy

satela [25.4K]

Answer:

Store A

Step-by-step explanation:

Store A costs $200.

Store B costs $240, with a 15% discount.

To solve how much the discount is, you do -

$240*0.85=204$

Since Store A is still cheaper, choose Store A.

4 0

2 years ago

How many hours would it take Natalie if she worked alone?

Annette [7]

It would take Natalie 6 hours by herself since she will finish in twice the time if she had Caesar to help.

3 0

1 year ago

If my dog is on a 5ft long leash, what is the area of the circle that he can run around in

xxMikexx [17]

Answer:

2/5

Step-by-step explanation:

vlabkajsheyevw8qvetegvhwhw

7 0

2 years ago

F(x)=x-6 move it 3 left then 2 up

Elza [17]

In the image move the point 3 left and 2 up then you should have your answer

5 0

2 years ago

What is the missing value in x2y8 · x3y? = x5y5?

sweet-ann [11.9K]

Answer:

-3

Step-by-step explanation:

To find:

The value of '?' in the following expression:

$x^2y^8.x^3y^? = x^5y^5$

Solution:

First of all, let us have a look at a few rules of the exponents:

$1.\ a^b.a^c=a^{b+c}$

$2.\ a^b.a^{-c}=a^{b-c}$

Let us apply these rules and try to find out the missing value ('?') in the given expression.

Left Hand Side (LHS):

$x^2y^8.x^3y^?\\\Rightarrow x^2.x^3.y^8.y^?\\\Rightarrow x^{2+3}y^{8+?}\\\Rightarrow x^{5}y^{8+?}$

Now, let us compare the LHS with RHS, we get:

$x^{5}y^{8+?} = x^{5}y^{5}$

Dividing with $x^5$ on both sides:

$y^{8+?} = y^5\\\Rightarrow 8+? = 5\\\Rightarrow ? = 5-8 \\\Rightarrow ? =-3$

Therefore, the missing value in the expression is <em>-3.</em>

4 0

2 years ago