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Charra [1.4K]
2 years ago
14

Andrew is building a scale model of an elephant. He determines that a real elephant is 10 feet tall and 14 feet long. If Andrew

wants his model to be 8 inches tall, how many inches long should his model be
Mathematics
1 answer:
Deffense [45]2 years ago
8 0
<h3>Answer:  11.2 inches</h3>

Work Shown:

(real height)/(scale height) = (real length)/(scale length)

(10 feet)/(8 inches) = (14 feet)/(x inches)

10/8 = 14/x

10x = 8*14

10x = 112

x = 112/10

x = 11.2 inches

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Answer:

20 hours

Step-by-step explanation:

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Name the property of multiplication that is shown by the equation 4x· 1 = 4x
Alex_Xolod [135]
Transitive property I believe
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What is the equation of a line with a slope of 4 and a y-intercept of 2?
Trava [24]

Answer:

y=4x+2 or f(x)=4x+2

Step-by-step explanation:

This is because the equation format for a line is y=mx+b, the slope is m and the y-intercept is b. So all you have to do is fill it out to get y=4x+2. Or the other way I listed the equation is right too. Hope this helps!

6 0
2 years ago
Read 2 more answers
One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
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What is seven times twenty
otez555 [7]
Question: What is seven times twenty
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