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garri49 [273]
2 years ago
5

120% of what number is 102 and how do you write the question? (Include a variable)

Mathematics
1 answer:
Nostrana [21]2 years ago
4 0

Answer:

y = 85

Step-by-step explanation:

120% times y = 102

That's how you write the equation.

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This graph shows the function relationship between the number of hours worked and the money earned. Use the information in the g
yaroslaw [1]

Answer:

A) $180

Step-by-step explanation:

7 0
3 years ago
Rewrite in simplest terms: -8(7y-8)-3(7y-7)−8(7y−8)−3(7y−7)
anzhelika [568]

Answer:

-8(7y-8)-3(7y-7)−8(7y−8)−3(7y−7)

Distribute to remove the parentheses.

Collect like terms

-154y+170

Step-by-step explanation:

7 0
3 years ago
10 times for thousands equals blank thousand equals blank
Marianna [84]
10×4,000=40,000 because all u do is add an extra zero everything you multiple something by ten
5 0
3 years ago
Which two lines are parallel?<br> 1. 5y =-3x-5<br> 2. 5y = -1-3x<br> 3. 3y - 2x = -1
liubo4ka [24]

Answer:

Lines 1 and 2.

Step-by-step explanation:

Parallel lines have the same slope. lines 1 and 2 both have a slope of -3

8 0
3 years ago
A data set includes 40 pulse rates of men, and those pulse rates have a mean of 67.3 beats per minute and a standard deviation o
Dafna11 [192]

Answer:

The 99% confidence interval of the  standard deviation of the pulse rates of men is  

       [ 7.949 \  \ , \  14.387 ]

Step-by-step explanation:

From the question we are told that

  The  sample size is  n  =  40

  The mean is  \= x  = 67.3 \  beats \  per \  minute

  The standard deviation is  s =  10.3 \ beats \ per \  minute

Generally the degree of freedom is mathematically represented as

     df =  n- 1

=>  df =  40- 1

=>  df =  39

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the chi distribution table the critical value  of   at a degree of freedom of is  

   X^2 _{\frac{\alpha }{2} , 39} =  65.476

Generally from the chi distribution table the critical value  of   at a degree of freedom of is  

   X^2 _{1- \frac{\alpha }{2} , 39} =  19.996

Generally the 99% confidence interval of the standard deviation of the pulse rates of men is mathematically represented as

  s \sqrt{\frac{n- 1}{X^2_{1- \frac{\alpha }{2} , n-1} } }\  \ , \ s \sqrt{\frac{n- 1}{X^2_{\frac{\alpha }{2} , n-1} } }

=>  10.3 \sqrt{\frac{40- 1}{65.476} }\  \ , \ 10.3 \sqrt{\frac{40- 1}{19.996} }

=>  [ 7.949 \  \ , \  14.387 ]

   

6 0
2 years ago
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