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sergey [27]
3 years ago
10

Tom jugs three fifth mile on Monday and to 6 mile on Tuesday how much farther did Tom jog on Monday, then on Tuesday.

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0
He jogged 4 2/5 miles more.
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Margo borrows $500, agreeing to pay it back with 3% annual interest after 14
Akimi4 [234]

Answer:

\$17.50

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest to pay

P is the amount of money borrowed

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=\frac{14}{12}\ years\\ P=\$500\\r=3\%=3/100=0.03

substitute in the formula above

I=500(0.03)(\frac{14}{12})

I=\$17.50

4 0
3 years ago
According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a
Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, \mu = 2.58 and Standard deviation, \sigma = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

             Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar \leq 2.50)

P(Xbar < 2.66) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } } ) = P(Z < -1.68) = 1 - P(Z  1.68)

                                                              = 1 - 0.95352 = 0.04648

P(Xbar \leq 2.50) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }  ) = P(Z \leq  -3.92) = 1 - P(Z < 3.92)

                                                              = 1 - 0.99996 = 0.00004  

Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046

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Step-by-step explanation:

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You express the values in which the teacher or tutor or whatever assigned you.

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