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2 years ago

Tom jugs three fifth mile on Monday and to 6 mile on Tuesday how much farther did Tom jog on Monday, then on Tuesday.

Mathematics

1 answer:

BartSMP [9]2 years ago

8 0

He jogged 4 2/5 miles more.

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Need help, really not good with anything in math

Anettt [7]

Answer:

D. 40.

Step-by-step explanation:

Find the reciprocal of 1/40:

1/40
= 40/1
= 40.

That's really it.

Your answer is 40 (D).

5 0

2 years ago

The perimeter of the square at the right is 48 in what is the area of the square at the right explain how you found your answer

irina1246 [14]

ok so 48÷4 is each side since square sides are equal that is 12 ×12 which is a area of 144

5 0

2 years ago

What is the solution to the equation

DIA [1.3K]

Answer: I got -8/9. Hope this helps in any way shape of form.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A shopkeeper buys pens at the rate of ₹ 75 per 100. for how much should he sell each pen so as to make a gain of 15%? please hel

Lady bird [3.3K]

Answer:

He should sell each pen of Rs.0.8625 so as to make a gain of 15%

Step-by-step explanation:

Cost price of 100 pens = Rs.75

Cost price of 1 pen= $\frac{75}{100}$ = 0.75

Gain%= 15%

Gain= $15%$ $X 0.75$ $= 0.1125$

SP = CP+Gain = 0.75+0.1125=0.8625

So, He should sell each pen of Rs.0.8625 so as to make a gain of 15%

#Learn more:

By selling 60 pens a shopkeeper gain the cp of 15 pen. If he bought 20 pens in rs36. Find the sp of one pen

brainly.in/question/15083989

https://brainly.in/question/7469007

3 0

3 years ago

☆pls help no one has helped me and I'm so confused!

motikmotik

Answer:

Step-by-step explanation:

a). $\frac{5\pm\sqrt{-4}}{3}$ = $\frac{5}{3}\pm \frac{\sqrt{-4}}{3}$

= $\frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}$

= $\frac{5}{3}\pm\frac{2i}{3}$ [Since, i = $\sqrt{(-1)}$ ]

b). $\frac{10\pm\sqrt{-16}}{2}$ = $\frac{10}{2}\pm \frac{\sqrt{-16}}{2}$

= $5\pm \frac{4\sqrt{-1}}{2}$

= 5 ± 2i [Since, i = $\sqrt{(-1)}$ ]

c). $\frac{-3\pm \sqrt{-144}}{6}$ = $-\frac{3}{6}\pm \frac{\sqrt{-144}}{6}$

= $-\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}$

= $-\frac{1}{2}\pm 2\sqrt{-1}$

= $-\frac{1}{2}\pm 2i$ [Since, i = $\sqrt{(-1)}$ ]

4 0

2 years ago