Tom jugs three fifth mile on Monday and to 6 mile on Tuesday how much farther did Tom jog on Monday, then on Tuesday.

What is 5minus e =25

ddd [48]

the answer is 125

5-e

= 5-25

= 125

5 0

2 years ago

Read 2 more answers

A baseball is thrown at an angle of 30° with respect to the ground and it reaches the ground in 2 seconds. What is its initial v

NeTakaya

Answer:

The answer to your question is vo = 19.62 m/s

Step-by-step explanation:

Data

angle = α = 30°

time = t = 2 s

vo = ?

g = 9.81 m/s²

Formula

$t = \frac{2vosin\alpha}{g}$

Solve for vo

$vo = \frac{tg}{2sin\alpha}$

Substitution

$vo = \frac{(2)((9.81)}{2sin 30}$

Simplification

$vo = \frac{19.62}{2(0.5)}$

$vo = \frac{19.62}{1}$

Result

vo = 19.62 m/s

3 0

2 years ago

If k is a positive integer and n = k(k + 7), is n divisible by 6 ? (1) k is odd. (2) When k is divided by 3, the remainder is 2.

olganol [36]

Answer:

1.) Yes

2.) Yes

Step-by-step explanation:

Given that

n = k(k + 7)

If k is a positive integer and n = k(k + 7), is n divisible by 6 ?

(1) k is odd. Yes.

Let assume that k = 3

Then, n = 3(3 + 7)

n = 3 × 10

n = 30.

30 is divisible by 6.

(2) When k is divided by 3, the remainder is 2. That is,

Let k = 5

Then,

5/3 = 1 remainder 2

Substitute k into the equation

n = k(k + 7)

n = 5(5 + 7)

n = 5 × 12

n = 60

And 60 is divisible by 6.

Therefore, the answer to both questions is Yes.

5 0

3 years ago

What is the answer for this question

VikaD [51]

i think the answer is c :)

6 0

2 years ago

Read 2 more answers

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment. Find the margin of error for the 95% confiden

Vlad [161]

Answer:

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.

This means that $n = 2161, \pi = \frac{1214}{2161} = 0.5618$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{0.5618*0.4382}{2161}}$

$M = 0.0209$

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

4 0

3 years ago