Question 9:
Given the equations
solving the system of the equations
( 0.5 is the result of rounding 0.5 to the nearest 0.01)
( 1.00 is the result of rounding 1 to the nearest 0.01 )
So, the solution is:
(x, y) → (1.00, 0.5)
Question 10)
Similarly the question 10 can be solved.
Given the equations
solving
( -8.00 Rounded to the nearest 0.01 or the Hundredths Place )
( 5.00 Rounded to the nearest 0.01 or the Hundredths Place )
So, the solution is:
(x, y) → (5.00, -8.00)
To determine how many oil changes you will need the first year, you can calculate the number of miles driven the first year and then use that to determine how many groups of 3000 miles you will drive after the first 5000 miles.
1. 52 x 250 = 13000 miles
2. 13000 miles - 5000 miles (1 oil change) = 8000 miles
3. 8000 miles - 3000 miles (1 oil change) - 3000 miles (1 oil change) = 2000 miles
The first year, you will need 3 oil changes.
Answer:
What translation from other point???????????????????????
Step-by-step explanation:
Answer:
$2355.06
Step-by-step explanation:
Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.
A = P(1 +r/n)^(nt)
where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.
Filling in the given values, we have ...
4000 = P(1 +.053/52)^(52·10) = P(1.6984738)
P = 4000/1.6984738 ≈ 2355.06
You would need to deposit $2355.06 in order to have $4000 in 10 years.
