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xz_007 [3.2K]
3 years ago
6

C.

Mathematics
1 answer:
Softa [21]3 years ago
6 0

Answer:

Lol I had the same question

Step-by-step explanation:

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What is the product? (4y - 3) (2y^2 +3y - 5)
igomit [66]

(4y-3)(2y²+3y-5)

First , let's start with "4y"

4y*2y² = 8y³

4y*3y =  12y²

4y*-5 = -20y

Next, let's multiply by "-3"

-3*2y² = -6y²

-3*3y = -9y

-3*-5 = 15

Now, let's combine all of our values.

8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15

8 0
2 years ago
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
2 years ago
I don't get this please can someone solve/ help me with this appreciate it thank you
Assoli18 [71]
It's scientific notation, so 1.4x10^7 would be 14000000 <span />
5 0
2 years ago
PLZ HELP !!! THIS TEST IS VERY IMPORTANT!!!!
andrew11 [14]

Answer:

E=20H

Step-by-step explanation:

E =20 when H=1

there fore the amount he receives per working time will be 20*H

8 0
3 years ago
Read 2 more answers
Which of the following equations have no solution? Check all that apply.
stealth61 [152]
6x+1 = 3(2x-4)
-4(x+3) = 4(x-1)
8 0
3 years ago
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