All categories

3 years ago

Due tomorrow!!!! 10 points!!

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

7 0

(1,2) -> reflect over y=x (angle 45°)
(2,1)
-> reflect over y=-x (angle -45°)
(-1, -2)

if you make a quick sketch then it's a lot easier to see why this is the case

You might be interested in

What is the solution

antoniya [11.8K]

Answer:

3,2 or 1

Step-by-step explanation:

5 0

3 years ago

PLEASE ANSWER CORRECTLY THANKS

Oksana_A [137]

Answer:

Step-by-step explanation:

......................

4 0

2 years ago

Read 2 more answers

A store finds that the number of shirts sold increases each week. In the first week, only 15 shirts were sold. In the next week,

Pepsi [2]

The explicit rule for the arithmetic sequence is a(n) = 7n + 8 if the arithmetic series is 15, 22, 29,...

<h3>What is a sequence?</h3>

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have:

In the first week, only 15 shirts were sold. In the next week, 22 shirts were sold and in the third week, 29 shirts were sold.

15, 22, 29,...

The first term a = 15

The common difference d = 22 - 15 = 7

a(n) = 15 + (n - 1)7

a(n) = 7n + 8

Thus, the explicit rule for the arithmetic sequence is a(n) = 7n + 8 if the arithmetic series is 15, 22, 29,...

Learn more about the sequence here:

brainly.com/question/21961097

#SPJ1

6 0

1 year ago

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

2 years ago

In the figure below, AB is a diameters of circle P what is the arc measure of AD in degrees

rusak2 [61]

Can I see a picture of the question

6 0

3 years ago

Read 2 more answers