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pshichka [43]
2 years ago
13

What is the distance from (−2, 4) to (0, −6)? round your answer to the nearest hundredth.

Mathematics
2 answers:
zavuch27 [327]2 years ago
4 0

Answer: 10.20

Step-by-step explanation: formula for distance between two points: d = √( (x₂ -x₁)² + (y₂ - y₁)²)x₁ = -2, y₁ = 4, x₂ = 0,  y₂ = -6d = √( (x₂ -x₁)² + (y₂ - y₁)²)d = √( (0 -  -2)² + (-6 - 4)²)d = √( (0 + 2)² + (-10)²)d = √( (2)² + (-10)²)d = √(4 + 100)d = √104        Use a calculator  ≈ 10.1980d ≈ 10.20 units    to the nearest hundredth

daser333 [38]2 years ago
3 0
Formula for distance between two points:

d = √( (x₂ -x₁)² + (y₂ - y₁)²)

x₁ = -2, y₁ = 4, x₂ = 0,  y₂ = -6

d = √( (x₂ -x₁)² + (y₂ - y₁)²)

d = √( (0 -  -2)² + (-6 - 4)²)

d = √( (0 + 2)² + (-10)²)

d = √( (2)² + (-10)²)

d = √(4 + 100)

d = √104        Use a calculator

d  ≈ 10.1980

d ≈ 10.20 units    to the nearest hundredth.
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igomit [66]

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500   ml     has   8 cloves

1 ml             has     8 / 500 cloves

100ml         has   8 / 500  * 100  =    8/5  = 1.6 cloves

Raphael's mixture  

    900 ml  has 12 cloves

      1 ml     has   12 / 900 cloves

   100 ml has   12 / 900 *  100   =    12 / 9  =   1.33 cloves

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3 years ago
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"Lito had some marbles. He gave ½ of his marbles plus 1 to Felix, ½ of the remaining marbles plus 1 to Ces, and ½ of the last re
Nuetrik [128]

let

x-------> total amount of marbles at the beginning


we know that

1) He gave ½ of his marbles plus 1 to Felix

(1/2)*x+1=(x+2)/2 (Felix's marbles)

remaining=x-[(x+2)/2]-----> [2x-x-2]/2------> (x-2)/2


2)½ of the remaining marbles plus 1 to Ces

(1/2)*[(x-2)/2]+1=[(x-2)/4]+1-----> (x+2)/4 (Ce's marbles)

remaining=[(x-2)/2]-[(x+2)/4]-----> [2x-4-x-2]/4------> (x-6)/4


3) ½ of the last remaining marbles plus 1 to Pedro

(1/2)*[ (x-6)/4]+1=[(x-6)/8)+1------> (x+2)/8 (Pedro's marbles)

remaining=[(x-6)/4]-[(x+2)/8]------> [2x-12-x-2]/8-----> (x-14)/8


4)If Lito had 1 marble left for himself

so

the last remaining is equal to 1

(x-14)/8=1-----> x-14=8------> x=22 marbles


Verify

(x+2)/2 (Felix's marbles)------> (22+2)/2=12

(x+2)/4 (Ce's marbles)------> (22+2)/4=6

(x+2)/8 (Pedro's marbles)---> (22+2)/8=3

Lito's marbles------------------> 1

total=12+6+3+1=22--------> is ok


therefore


the answer is

the total amount of marbles at the beginning was 22

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