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Rus_ich [418]
3 years ago
5

Help with homework Algebra 2:

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:

12y^2+2y-5

Step-by-step explanation:

(72y^3 + 12y^2 - 30y) ÷ 6y

WE divide each term by 6y, while dividing by 6y we apply property of exponent

a^m / a^n= a^m-n

\frac{72y^3}{6y} =12y^2

\frac{12y^2}{6y} =2y

\frac{30y}{6y} =5

Now we combine all the terms

12y^2+2y-5

Darina [25.2K]3 years ago
6 0
The answer is 12y^2 + 2y - 5
The solution:
(72y^3 + 12y^2 - 30y) / 6y =
(6y)*(12y^2 + 2y - 5) / 6y = 12y^2 + 2y - 5
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given y&gt;0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
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