Ask question

Ask question

All categories

3 years ago

13

How are units of length and capacity similar in the metric system

1 answer:

fiasKO [112]3 years ago

8 0

In the metric system, each of the common kinds of measure -- length, weight, capacity -- has one basic unit of measure. To measure smaller amounts, divide the basic unit into parts of ten, a hundred, or a thousand, and so on. To measure larger amounts, multiply the basic unit by ten, a hundred, or a thousand, and so on.
Length:
1 kilometer (km) = 1000 meters (m)
1 centimeter (cm) = .01 meter (m)
1 millimeter (mm) = .001 meter (m)
Weight:
1 kilogram (kg) = 1000 grams (g)
1 milligram (mg) = .001 gram (g)
Capacity:
1 milliliter = .001 liter (l)

You might be interested in

Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

5 0

3 years ago

An article fills 5/8 of a magazine page. A

Shalnov [3]

Answer:

35

Step-by-step explanation:

bundles tundra dismay chard bff dusk m u

5 0

3 years ago

Read 2 more answers

Is it aaaaaaaa or dddddddd

nika2105 [10]

Its none
because a triangle makes up 180 degrees hope this helps and im not a dumby

4 0

4 years ago

Read 2 more answers

Pls help me for brainliest answer

Oksana_A [137]

Answer:

1.17 euros

I just did this question and got it right)

please mark as brainliest

3 0

4 years ago

Find the projection of u onto v<br> URGENT HELP

padilas [110]

Given:

Two vectors are:

$u=\left$

$v=\left$

To find:

The projection of u onto v.

Solution:

Magnitude of a vector $v=\left$ is:

$|v|=\sqrt{a^2+b^2}$

Dot product of two vector $v_1=\left$ and $v_2=\left$ is:

$v_1\cdot v_2=a_1a_2+b_1b_2$

Formula for projection of u onto v is:

$Proj_vu=\dfrac{u\cdot v}{|v|^2}v$

$Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left$

$Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left$

$Proj_vu=\dfrac{0+102}{293}\left$

On further simplification, we get

$Proj_vu=\dfrac{102}{293}\left$

$Proj_vu=\left$

$Proj_vu=\left$

Therefore, the projection of u onto v is $Proj_vu=\left$ .

3 0

3 years ago