HELP PLEASE!‼️‼️‼️!!!!!

les uses pencils every 5 weeks to do his school work and homework. if les were to plot these numbers on a graph with the pencils

lina2011 [118]

Answer:

I'm not sure but i think it is 5

5 0

3 years ago

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What is the roasting time for a 12-pound turkey?

NeX [460]

The roasting time for a 12 pound turkey is 3 hours

5 0

2 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) Center of the circle is translated 4 units to the right (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) Reflection over the x-axis:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

4 0

3 years ago

What is 1.086 rounded to the nearest whole number

Andru [333]

1.086 rounded to the nearest whole number would remain as one.

This is due to the fact that the tenths place does not have any number, and due to this the whole number would remain one.

If the number were to change, it would look as the following:

1.5 rounded to the nearest whole number 2.

3 0

3 years ago

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Complete the square to find the vertex of this parabola. x2-16y-4x-12=0

lana [24]

Answer:

Step-by-step explanation:

x^2-16y-4x-12=0

Transpose and separate x and y

16y = x^2-4x-12

16y = (x^2-4x+4) -16

16y = (x-2)^2 -16

y = (1/16)(x-2)^2 -1

This means that the vertex is at

(x-2)=0 or x=2

y = -1

=> vertex (2,-1)

6 0

3 years ago