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KIM [24]
3 years ago
5

You borrow ​$600 from a friend the first week and pay the friend back ​$20 each week there after. Write the first six terms in t

he sequence.
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
1st term: 20 dollars
 2nd term:40 dollars
3rd term: 60 dollars
4th term:80 dollars
5th term:100 dollars
6th term:120 dollars
 I hope this is correct.
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A piece of cloth was 30 feet long. how long is this cloth in yards? one yard = 3 feet​
Alinara [238K]

Answer:

10 yards

Step-by-step explanation:

Every 1 yard is 3 feet, the cloth is 30 feet
30 ÷ 3 = 10

The cloth is 10 yards.

Hope this helps!

7 0
2 years ago
What number would complete the pattern below? 66 73 13 21 52 __ 10 20
Serhud [2]
The answer is d.61. 66+7=73. 13+8=21. 52+9=61. 10+10=20
3 0
3 years ago
Read 2 more answers
In ABC, BC = a = 16, AC = b = 10, and m<C = 22º. Which equation can you use to find the value of c = AB?
AnnyKZ [126]

Answer:

10 times 16 = C

Step-by-step explanation:

c2 = a2 + b2 − 2ab cos C = 162 + 102 − 2(10)(16) cos 22°

5 0
3 years ago
What is the converse of t > r
Anettt [7]

The converse of  t > r is r > t

<h3>What is a converse statement?</h3>

A converse statement is determined when both the hypothesis and conclusion are reversed or interchanged.

In this condition, the hypothesis is written as the conclusion and the conclusion is changed to be the hypothesis.

If a conditional statement is written as: x → y

The converse is then written as y → x

Where;

  • x is the hypothesis
  • y is the conclusion

Given the expression as;

t > r

We can see that;

  • The variable 't' is the hypothesis
  • The variable 'r' is the conclusion

The converse will be;

r > t

Hence, the converse is r > t

Learn more about converse statement here:

brainly.com/question/3965750

#SPJ1

6 0
1 year ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
2 years ago
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