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svet-max [94.6K]

3 years ago

7

A football team gains 3 yards on the first play ,loses 6 yards on the second play,loses 4 yards on the third play , and gains 5

yards on the fourth play. What is the team's overall gain or loss for all four plays?

2 answers:

galben [10]3 years ago

5 0

Net yardage=3-6-4+5=-2

So the team lost 2 yards in four plays...

PtichkaEL [24]3 years ago

4 0

It is 3-6-4+5= -2

I think not sure

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Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)

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<u>Step-by-step explanation:</u>

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$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\$

Next, find the midpoint of (4, 1) and (2, -5):

$Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)$

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3 years ago