Answer:
The Answer is that Senior Citizen Tickets cost: $4 and Child tickets cost: $7.
Step-by-step explanation:
Let s = the cost of senior citizen tickets
Let c = the cost of child tickets
The number of tickets sold for each type added together equals the sales for each day. Equations below:
Day 1
3s + 9c = $75
Solve for s:
3s = 75 - 9c
s = 25 - 3c
Day 2
8s + 5c = $67
By substitution:
8(25 - 3c) + 5c = 67
200 - 24c + 5c = 67
-19c = -133
c = -133 / -19 = $7 cost for child tickets.
Solve for s:
s = 25 - 3c
s = 25 - 3(7)
s = 25 - 21 = $4 cost for senior citizen tickets.
Proofs:
Day 1
3s + 9c = $75
3(4) + 9(7) = 75
12 + 63 = 75
75 = 75
Day 2
8s + 5c = $67
8(4) + 5(7) = 67
32 + 35 = 67
67 = 67
Answer:
x=50
Step-by-step explanation:
Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
Area1:Area2=pi(2R)^2:pi(5R)^2=pi(4R^2):pi(25R^2), pi cancel out we get
4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
3x-3y+0+1-1 Just tack on something onto it that doesn't change the outcome
