Question

Write the​ slope-intercept form of the equation of the line satisfying the given conditions. through ​(1 ​,6​); slope negative 4

Answer 1

Slope intercept form of a line is y=mx+b where m= slope and b=y-intercept.

Given slope:m= -4 and the line passes through (1,6).

Point slope form of a line is:

$y-y_{1} =m(x-x_{1} )$

So, first step is to plug in m=-4, x1=1 and y1=6 in the above equation. So,

y-6=-4(x-1)

y-6=-4x+4 By distribution property.

y=-4x+4+6 Add 6 to each sides of the equation.

y=-4x+10

So, slope intercept form is y=-4x+10.