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Galina-37 [17]
4 years ago
9

The sphere weighs .075pound per cubic inch if the sphere radius is 4inches what is the weight to the sphere to the nearest pound

Mathematics
1 answer:
Dafna11 [192]4 years ago
5 0
Sphere Volume<span> = 4/3 • <span>π <span>• r³
</span></span></span>Sphere Volume<span> = 4/3 • <span>π <span>•radius^3
</span></span></span>Sphere Volume = <span> <span> <span> 268.08</span></span></span> cubic inchesSphere weight = <span> <span> 268.08 * .075
</span></span>Sphere weight = 20.106 pounds =20 pounds (rounded)


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Following the setps we have that

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the lengths of the sides of the original square is 8 inches each one. Now we are going to find the lengths of the sides of the new square following the step 2

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Answer:

P(32) = \frac{1}{90}

P(Odd) = \frac{1}{2}

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Step-by-step explanation:

Given

Sample Space = 10 to 99

First, we calculate the sample size (n)

n = 99 - 10 + 1

n = 90

Solving (a): P(32)

In 10 to 99, there is only 1 32.

So,

P(32) = \frac{n(32)}{n}

P(32) = \frac{1}{90}

Solving (b): P(Odd)

There are 45 odd numbers between 10 and 99

i.e.

n(Odd)  = 45

So:

P(Odd) = \frac{n(Odd)}{n}

P(Odd) = \frac{45}{90}

P(Odd) = \frac{1}{2}

Solving (c): P(Multiple of 5)

There are 18 multiples of 5 between 10 and 99

i.e

P(Multiples\ 5) = \frac{18}{90}

P(Multiples\ 5) = \frac{1}{5}

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