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Leya [2.2K]
3 years ago
10

What is p=6-2q, p=1+q, how do I use on graph

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0
1] ⬇
p - (6 - 2(q))➡0
p + 2q - 6➡0
q = 3 because 6÷2 = 0
p = 6 because 6 ÷ 1 = 6
Slope ➡ 0.5
-----------------------------------------------------------------
2] ⬇
p - (1 + q)➡0
p - q- 1➡0
Q = -1 because 1 ÷ -1 ='-1
P = 1 because 1 ÷ 1 = 1
Slope ➡ 1
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Use Synthetic Division to divide 6x^3-10x^2+20 by x+1<br><br> Quotient:_____<br><br> Remainder:_____
exis [7]

Answer:

the quotient is 6x^2 - 16x + 16, and the remainder is just 4

Step-by-step explanation:

The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}.  Division by the binomial x + 1 requires that we use -1 as the divisor.  The synthetic division setup becomes:

-1   /    6    -10    0    20

                 -6    16   -16

     -----------------------------

          6     -16   16       4

Taking the coefficients {6, -16, 16}, we write the quotient as

6x^2 - 16x + 16, and the remainder as just 4.

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3 years ago
How long would it take the two trains to meet?
tiny-mole [99]

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Step-by-step explanation:

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2 years ago
6x + 3y + z = 21<br> y = 7x + 8z - 29<br> -6y - 8z = 6
kicyunya [14]

Answer:

What is the question

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4 0
2 years ago
Read 2 more answers
write an equation in slope intercept form of the line with a slope- 2 and y intercept 3. Graph the line
charle [14.2K]

Answer:

y = -2x + 3

Step-by-step explanation:

<u>Step 1:  Find out what each part of slope intercept form is</u>

Slope Intercept Form:  y = mx + b

<em>m is the slope</em>

<em>b is the y-intercept</em>

<u>Step 2:  Plug in the information into the formula</u>

m/slope = -2

b/y-int = 3

<em>y = -2x + 3</em>

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4 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
2 years ago
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