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Leya [2.2K]
3 years ago
10

What is p=6-2q, p=1+q, how do I use on graph

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0
1] ⬇
p - (6 - 2(q))➡0
p + 2q - 6➡0
q = 3 because 6÷2 = 0
p = 6 because 6 ÷ 1 = 6
Slope ➡ 0.5
-----------------------------------------------------------------
2] ⬇
p - (1 + q)➡0
p - q- 1➡0
Q = -1 because 1 ÷ -1 ='-1
P = 1 because 1 ÷ 1 = 1
Slope ➡ 1
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2x + 9 = 5x

5x = 2x + 9

Subtract sides 2x

- 2x + 5x = - 2x  + 2x + 9

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Divide sides by 3

\frac{3x}{3}  =  \frac{9}{3}  \\

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CHECK :

2x + 9 = 5x

2(3) + 9 = 5(3)

6 + 9 = 15

15 = 15

So the value is correct.

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What are the apparent zeros of the function graphed above. (-0.7, -2,7)
castortr0y [4]

Answer:

x ∈ {-2, 1, 4}

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3 0
3 years ago
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