A hole occurs when both numerator and denominator of a rational function have the same factor.
<u>Step-by-step explanation:</u>
While graphing rational function, it has to be converted into the lowest terms by factoring the numerator and denominator. If the numerator and denominator has the same factor, a hole is said to have occurred and to solve the rational function, you have to set the common factor to zero.
After you set it to zero and solve, you obtain the x value which can be then used to find out the value of y.
Answer:
64k^2 - 16k +1
Step-by-step explanation:
We can rewrite this as
(-8k+1) ^2
We know that (a+b)^2 = a^2 +2ab +b^2
Let a = -8k and b = 1
(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2
=64k^2 - 16k +1
Answer:
61.69?
Step-by-step explanation:
Are you asking what 31% of 119 is? If so, then the answer would be 61.69.
Because (119)0.31=61.69
(To make a percent, you take a decimal out of 1, and multiply. 0.31 would be 31, because we would multiply it by 100, becuase you can only get to 100%. Then you woukd do the opposite, reverse it by dividing by 100. Which then, you would get 0.31)
Hope that helped.
A. √(0.8^2) + (0.6^2) = √1 = 1 => OK
<span>b.(-2/3,√ 5/3) = √(-2/3)^2 + 5/9) = √(4/9 +5/9) = √1 = 1 => OK
c.(√ 3/2, 1/3) = √(3/4 + 1/9) < 1 => it is inside the unit circle
d.(1,1)
= √(1 + 1) = √2 > 1 => NO. This point is beyond the limits of the unit circle.</span>
I really believe the correct answer is 2.64 miles but if I am wrong I truly apologize
