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vladimir1956 [14]
3 years ago
5

Ming bought a watermelon with the mass of 6 kilograms she cut off the rind the remaining watermelon had a mass of 2500 grams wha

t was the mass of the rind
Mathematics
1 answer:
dezoksy [38]3 years ago
4 0
First we convert 6 kg to grams which should be 6000 grams, since there are 1000 grams in one kg. 

Subtract 2500 from 6000 and we get 3500 grams, which is your answer
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Step-by-step explanation:

First you have to convert each number to improper fractions.

Next you have to multiply denominator to denominator, and fraction to fraction.

Then simplify your final answer to the lowest form possible.

Hope this helps :)

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6) 2/3 is this a integer, whole number, or a rational number.​
AlekseyPX

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rational number

Step-by-step explanation:

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Another way to write 9 x 200
Katyanochek1 [597]
200+200+200+200+200+200+200+200+200
6 0
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A circle has the equation (x-2)^2 +y^2 =5. What are the coordinates of the circle's center?
Elina [12.6K]
The circle with center (h, k) and radius r has equation
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3 0
3 years ago
Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f
Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

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P(A) = 0.1*0.8 + 0.25*0.2 = 0.13

Probability that a student is foreign and undergraduate:

10% of 80%. So

P(A \cap B) = 0.1*0.8 = 0.08

What is the probability that the student is an undergraduate?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154

0.6154 = 61.54% probability that the student is an undergraduate

8 0
3 years ago
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