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marysya [2.9K]
2 years ago
13

A swim meet has 13 contestants signed up for the 100-meter butterfly event. The first heat has 6 swimmers. How many different wa

ys can the contestants be arranged in the first heat?
Mathematics
1 answer:
tino4ka555 [31]2 years ago
5 0

Answer:

6 swimmers in the first heat can be arranged in 1716 different ways.

Step-by-step explanation:

A swim meet has 13 contestants signed up. To calculate the arrangement of first 6 swimmers in first heat we will use combinations because order doesn't matter.

So to select 6 swimmers out of 13 contestants number of different ways

= ^{13}C_{6}

= \frac{13!}{(6!)(13-6)!}

= \frac{13\times 12\times 11\times 10\times 9\times 8\times 7!}{6!\times 7!}

= \frac{13\times 12\times 11\times 10\times 9\times 8}{6\times 5\times 4\times 3\times 2\times 1}

= \frac{1235520}{720}

= 1716

Therefore, 6 swimmers in the first heat can be arranged in 1716 different ways.

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A rectangular poster has an area of 190 inches squared. The height of the poster is one inch less than twice its width. Find the
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Set the height to h, and the width to w.

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Substituting 2w-1 for h, we have:

w(2w-1)=190

So:
2w^2-w-190=0

Factoring this equation, we get (2w+19)(w-10)=0.  The solutions to this equation are -9.5 and 10, but clearly the width must be positive, Substituting 10 for the width, we get 10*2-1=19 for the height.
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7 0
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In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti
weqwewe [10]

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

x=\frac{-2-\sqrt{19}}{3}  and  x=\frac{-2+\sqrt{19}}{3}

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}

To find the solution of the quadratic equation by using quadratic formula

  • Find the values of a, b, and c from the quadratic equation
  • Substitute these values in the quadratic formula
  • Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}

∴ x=\frac{4+\sqrt{16+60}}{-6}

∴ x=\frac{4+2\sqrt{19}}{-6}

- Simplify by dividing up and down by -2

∴ x=\frac{-2-\sqrt{19}}{3}

∵ x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}

∴ x=\frac{4-\sqrt{16+60}}{-6}

∴ x=\frac{4-2\sqrt{19}}{-6}

- Simplify by dividing up and down by -2

∴ x=\frac{-2+\sqrt{19}}{3}

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

x=\frac{-2-\sqrt{19}}{3}  and x=\frac{-2+\sqrt{19}}{3}

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

#LearnwithBrainly

9 0
3 years ago
Read 2 more answers
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