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marysya [2.9K]
3 years ago
13

A swim meet has 13 contestants signed up for the 100-meter butterfly event. The first heat has 6 swimmers. How many different wa

ys can the contestants be arranged in the first heat?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

6 swimmers in the first heat can be arranged in 1716 different ways.

Step-by-step explanation:

A swim meet has 13 contestants signed up. To calculate the arrangement of first 6 swimmers in first heat we will use combinations because order doesn't matter.

So to select 6 swimmers out of 13 contestants number of different ways

= ^{13}C_{6}

= \frac{13!}{(6!)(13-6)!}

= \frac{13\times 12\times 11\times 10\times 9\times 8\times 7!}{6!\times 7!}

= \frac{13\times 12\times 11\times 10\times 9\times 8}{6\times 5\times 4\times 3\times 2\times 1}

= \frac{1235520}{720}

= 1716

Therefore, 6 swimmers in the first heat can be arranged in 1716 different ways.

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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
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Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

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Substitute, we get,

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Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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