184 milliliters of the first brand and 46 milliliters of the second brand
Step-by-step explanation:
Step 1:
Let x be the number of milliliters of the first brand in the final mixture
Since the chef requires 230 milliliters, 230 - x would be the milliliters of dressing of the second brand
Step 2:
The first brand contains 6% vinegar, and the second brand contains 11% vinegar
Hence we have,
x * 6/100 + (230-x) * 11/100 = 230 * 7/100
0.06 x + 25.3 - 0.11 x = 16.1
0.05x = 9.2 => x = 184
Hence the 184 milliliters of the first brand is to be used
Step 3 :
Quantity of the second brand to be used is 230 - x = 230 -184 = 46 milliliters.
Answer:
2500 ft²
Step-by-step explanation:
The missing area at lower right in the diagram has dimensions...
(4-2 1/4) by (3 - 1 3/4) by (1 1/4)
Then area of that "Missing" space is (1.75)(1.25)= 2.1875 . . . . square inches. The area of the enclosing rectangle is ... (4 in) (3 in) = 12 square inches the area in the diagram representing the store is... 12 in² -2.1875 in² = 9.8125 in²
_
Each square inch on that diagram represents an actual area of (1 in)×(1 in) → (16 ft)×(16 ft) = 265 ft²
Then the actual store area is....
9.8125(256 ft²) = 2512 ft²
Rounded to the nearest 50 ft², this is 2500 ft².
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
