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bagirrra123 [75]
3 years ago
13

At the bank, Sheila made 5 deposits, each in the same amount. Her sister Sherri made 4 deposits, each in the same amount. Each o

f Sherri's deposits was $15 more than each deposit Sheila made. Both sisters deposited the same amount in the end. How much did each sister deposit each time?
- Write an equation. Let x represent the amount of one of Sheila’s deposits.
- Solve the equation. Show your work.
- Check your solution. Show your work.
- State the solution in complete sentences.
Mathematics
2 answers:
irinina [24]3 years ago
5 0

The equation would be 4y=5x       4(x+15)=5x             x+15=y

let x be the amount that Shelia deposits each time

let y represent the amount that Sherri deposits each time

4(x+15)=5x

4x+60=5x

-4x       -4x

60=x

Check:

x+15=y                  60+15=y                        y=75

4(75)=5(60)

300=300

Shelia deposits $60 each time.

sasho [114]3 years ago
3 0

DERIVAR :

(2x – 1) / √ x2 + 1



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The inequality 10.45b + 56.50 &lt; 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceedin
nordsb [41]

Question :

The inequality 10.45b + 56.50 < 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceeding the weight limit of the truck. The solution is written as {b | b < 22.6}. Which statement best describes the meaning of the solution?

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The truck can hold up to 23 boxes.

Answer:

Option C: The truck can hold up to 22 boxes.

Explanation:

Given that the inequality is 10.45b + 56.50 < 292.67 is used to find the number of boxes can be loaded on a truck without exceeding the weight limit of the truck.

To determine the number of boxes, let us solve the inequality.

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Subtracting both sides by 56.50, we get,

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Dividing both sides by 10.45, we have,

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The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

<h3>How to determine the sum of the notation?</h3>

The sum notation is given as:

∞Σn=1 2(1/5)^n-1

The above notation is a geometric sequence with the following parameters

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The sum is then calculated as

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