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VLD [36.1K]
3 years ago
9

I need help please.

Mathematics
1 answer:
GuDViN [60]3 years ago
4 0

Answer:

The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

Step-by-step explanation:

The given expression is:

2q²-5pq-2q+5p

Make a pair of first two terms and last two terms:

(2q²-5pq) - (2q-5p)

Now factor out the common factor from each group.

Note that there is no common factor in second group. So we will take 1 as a common factor.

q(2q-5p) -1(2q-5p)

Now factor the polynomial by factoring out the G.C.F, 2q-5p

(2q-5p) (q-1)

Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

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Ka-Sean Hall has a single membership in his company's health insurance program. The total cost is $4,856
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Answer: I might of got it totally wrong but I got $5,070.00

Step-by-step explanation:

4 0
3 years ago
What is the root of the polynomial equation *(x-2)(x+3) - 18? Use a graphing calculator and a system of
zysi [14]

Answer:

Start by using your first factor, 1. Substitute "1" for each "x" in the equation: (1)3 - 4(1)2 - 7(1) + 10 = 0.

This gives you: 1 - 4 - 7 + 10 = 0.

Because 0 = 0 is a true statement, you know that x = 1 is a solution.

Step-by-step explanation:

Start by using your first factor, 1. Substitute "1" for each "x" in the equation: (1)3 - 4(1)2 - 7(1) + 10 = 0.

This gives you: 1 - 4 - 7 + 10 = 0.

Because 0 = 0 is a true statement, you know that x = 1 is a solution.

5 0
3 years ago
Read 2 more answers
The area of a playground is 204 yd^2 the width of thr playground is 5 yd longer that its length what the length and the width of
morpeh [17]
W= width= L+5
L= length
Area= 204

Area= LW
204 square yards= LW
substitute w=L+5 for w
204= (L)(L+5)
204= L^2 + 5L
subtract 204 from both sides
0= L^2 + 5L - 204
factor
0= (L+17)(L-12)

0= L+17
-17= L

0= L-12
12 yards= L


WIDTH
Since the area cannot be a negative number, we'll use L=12 to find the width.

w=L+5
w=12+5
w=17 yards


CHECK:
204=(12)(17)
204=204


ANSWER: The length is 12 yards and the width is 17 yards.

Hope this helps! :)
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8,6,2, and 1

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7 0
4 years ago
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