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2 years ago

If 9 = 5 + 4 and 5 + 4 = 3 + 6, then 9 = 3 + 6. This is an example of which property?

Mathematics

2 answers:

Anna007 [38]2 years ago

8 0

B. Transitive Property

Kazeer [188]2 years ago

4 0

I think it would be b transitive property

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What is the exact value for the expression the square root of 189. − the square root of 21. + the square root of 84.? Simplify i

klemol [59]

<span>It's 4 the square root of 21</span>

7 0

2 years ago

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

4 0

2 years ago

What is the perimeter of a triangle with the given side lengths?

saul85 [17]

The perimeter of any shape is the distance all the way around it.

For a triangle, it's the sum of the three side lengths.

I would normally copy them into my answer and then add them up.
But you've set them up in such a beautiful table in the question,
you can just look at that list and add them up.

Add up all the x's : x + x + x = 3x

Add up all the plain numbers: -3 + 2 + 4 = 3

There's your perimeter . . . . . 3x + 3 .

5 0

2 years ago

Solve for this trig identity step by step.

stepladder [879]

Using trigonometric identities, and equality is reached, hence the equality is proved.

<h3>Which trigonometric identity are used to solve this question?</h3>

These three identities are used:

$\sin^2{x} + \cos^2{x} = 1 \rightarrow \cos^2{x} = 1 - \sin^2{x}$ .

$\sec^2{x} = 1 + \tan^2{x}$ .

$\sec^2{x} = \frac{1}{\cos^2{x}}$

Hence:

$\sec^4{x} = \frac{1 + \tan^2{x}}{1 - \sin^2{x}}$

$\sec^4{x} = \frac{\sec^2{x}}{\cos^2{x}}$

$\sec^4{x} = \sec^2{x} \times \sec^2{x}$

$\sec^4{x} = \sec^4{x}$

Equality is reached, hence the equality is proved.

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

4 0

1 year ago

Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f

nata0808 [166]

Via Lagrange multipliers:

$L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)$
$L_x=2xy+1+\lambda y=0$
$L_y=x^2+1+\lambda x=0$
$L_\lambda=xy-5=0$

$\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y$
$xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x$

$\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}$
$xy=5\implies y=\pm\sqrt{30}$

At these points, we get local minima of $f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}$ .

- - -

Another way to do this is to make $f(x,y)$ a function independent of $y$ , which is made possible by the constraint.

$xy=5\implies y=\dfrac5x$
$\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x$
$\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}$

and so on.

8 0

2 years ago