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2 years ago

7

A bag contains 6 blocks:2green,1black,1white,and 2orange.if the event is drawing a black block,find the number of favorable outc

omes.

1 answer:

beks73 [17]2 years ago

5 0

Answer:

have u tried to google it

Step-by-step explanation:

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PLEASE CAN ANYONE HWLP WITH THIS QUESTION I NEED HELP ASAP!!!!!!

matrenka [14]

Answer: C.) $51

Step-by-step explanation:

$85.00 x 40%

85.00 x 0.40= 34

85.00-34=51.00

$51

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2 years ago

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nadya68 [22]

Pythagorean Theorem
75^2+40^2=x^2
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Square root of 7225 is 85
So hypotenuse is 85 yd

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3 years ago

27n⁵+75n³ (Factor completely)

dimaraw [331]

Answer:

3n^2 (9+25n)

Step-by-step explanation:

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2 years ago

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13.......................

Alla [95]

Answer:

The answer is (d) ⇒ $pq^{2}r\sqrt[3]{pr^{2}}$

Step-by-step explanation:

* To simplify the cube roots:

If its number then the number must be written in the form x³

then we divide the power by 3 to cancel the radical

If its variable we divide its power by 3 to cancel the radical

∵ $\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}$

∴ $p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}$

∵ $p^{\frac{1}{3}}=\sqrt[3]{p}$

∵ $r^{\frac{2}{3}}=\sqrt[3]{r^{2}}$

∴ $p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})$

∴ $prq^{2}\sqrt[3]{pr^{2}}}$

∴ The answer is (d)

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2 years ago

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OleMash [197]

seth2cold let’s be moots

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