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IrinaVladis [17]
3 years ago
6

Write the ratio for cos B

Mathematics
2 answers:
Bingel [31]3 years ago
6 0

<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em>

Sholpan [36]3 years ago
3 0

Answer:

cos B = \frac{7}{25}

Step-by-step explanation:

cos B = \frac{adjacent}{hypotenuse} = \frac{BC}{AB} = \frac{7}{25}

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F ( x ) = -3 ( x + 4 ) ( x - 6 )
Sunny_sXe [5.5K]
Not sure what you’re asking, but, if you’re looking for the expanded form... hope that helps?

3 0
3 years ago
How do you factor 125-x^3?
xz_007 [3.2K]

Step-by-step explanation:

We have

125 - x {}^{3}

First, 125 is a perfect cube because

5 \times 5 \times 5 = 125

and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

64 - 27

we know that

64 - 27 = 37

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

1(16 + 12 + 9) = 1(37) = 37

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

(5 - x)( {5}^{2}  + 5x +  {x}^{2} ) =

(5 - x)(25 + 5x +  {x}^{2} )

3 0
2 years ago
Read 2 more answers
M×10+m×13=138<br><br>sorry theres another loll I'm so bad at these
Dimas [21]
So first of all you would add the two together
so it would be m23.

138÷23 would equal 6,

therefore m would equal six

to check it substitute m for 6 and you should get 138!
7 0
3 years ago
One and three seven divided by two
Vladimir [108]

Answer:

0.7 or 5/7

Step-by-step explanation:

(1 3/7) ÷ 2 =

8 0
3 years ago
What is the solution to the equation?
pashok25 [27]

Answer:

x= 27

Step-by-step explanation:

Move <u>constant</u> to the right-hand side and change its sign.

\sqrt{2x+10} = 2+6

Add the numbers.

\sqrt{2x+10}= 8

Square both sides of the equation.

2x+10= 64

Move the <u>constant</u> to the right-hand side and change its sign.

2x= 64-10

Subtract the numbers.

2x= 54

Divide both sides of the equation by 2.

x= 27

4 0
3 years ago
Read 2 more answers
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