Answer:
Actual distance represented by 5.5 inch of map distance is
miles
Step-by-step explanation:
Given,
The scale of map -
1 inch on map is equal to 35 miles.
Distance measured by mike on map is equal to 5.5 inch
Actual distance represented by 5.5 inch of map distance is
miles
Step-by-step explanation:
16. Length of a line = sqaureroot of ((x1-x0)^2 - (y1- y0)^2)
C (2,-3) D (6,3)
CD = sqaureroot of ((6-2)^2 + (3-(-3))^2)
CD = sqaureroot of ( 16 + 36)
CD = sqaureroot of 52 = 2 root 13 = length
17. E (5, - 1) because the point is under the x axis.
Midpoint = ((x1+ x0)/2 , (y1 +y0) /2)
B (8,1) C (2, - 3)
Midpoint of BC = ((2+8)/2 , (-3+1)/2)
= (10/2 , - 2/2)
= (5, - 1)
18. Length of AE
A (4,5) E(5,-1)
Square root of ((5-4)^2 + (-1-5)^2)
Square root of (1^2 + - 6^2)
Square root of ( 1 + 36)
Square root of 37 = root 37
Please gimme brainliest
3d + 8 = 2d - 7 equals d = -15.
First, subtract 2d from both sides. Your problem should look like: 3d + 8 - 2d = -7.
Second, simplify 3d + 8 - 2d to get d + 8. Your problem should look like: d + 8 = -7.
Third, subtract 8 from both sides. Your problem should look like: d = -7 - 8.
Fourth, simplify -7 - 8 to get -15. Your problem should look like: d = -15, which is your answer.
Hopefully this helps, I'm not exactly sure what you meant by "is equations," but this is how you solve the problem.
Answer:
The traditional scale consists of two plates or bowls suspended at equal distances from a fulcrum. One plate holds an object of unknown mass (or weight), while known masses are added to the other plate until static equilibrium is achieved and the plates level off, which happens when the masses on the two plates are equal. The perfect scale rests at neutral. A
