I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
j =76/3
Step-by-step explanation:
-3j - -4
------------------ = 12
-6
Multiply each side by -6 to clear the fraction
-3j +4
------------------ * -6 = 12 *-6
-6
-3j +4 = -72
Subtract 4 from each side
-3j +4-4 = -72 -4
-3j = -76
Divide each side by -3
-3j/-3 = -76/-3
j = 76/3
The original price is 67 and 4 percent dissocount
Answer:
The last option
Step-by-step explanation:
You take the middle 2 numbers, add them up, and divide by 2.
