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ExtremeBDS [4]
3 years ago
7

A candy factory that produces chocolate bars claims each bar weighs 50 grams, at least that is what is printed on the label. Of

course, there is bound to be a little variation. An inspector randomly chooses 16 bars from one day's output of 4000 bars. The average weight of the 16 bars is only 48.5 grams. The inspector wishes to test the null hypothesis that the factory is doing what it is supposed to on this day against the alternative that the company is cheating the consumer. Assume that the weights of all the candy bars that are produced follow the normal curve with a SD of 2 gram(s).
Which significance test should be used?
A z test because the SD of the population is known and the weights follow the normal curve. You are correct. Computer's answer now shown above Previous Tries Your receipt no. is 159-2320
Do you need to use SD+ o estimate the SD of the population?
No, we're given the SD of the population, we don't need to estimate it. Incorrect.
Computer's answer now shown above ries 1/1 Previous Tries
Compute SE. (Give your answer as a decimal to two places) Submit Answer Tries 0/5
Compute the test statistic. (Round your answer to two decimals, using previously rounded answer.) Submit Answer Tries 0/5
What do you conclude?
A. Reject the null, it's very unlikely that the factory is making the candy bars 50 grams as they claim.
B. Cannot reject the null, it's plausible that the factory is making the bars 50 grams as they claim to be doing. Submit Answer Tries 0/1

Mathematics
1 answer:
Romashka [77]3 years ago
5 0

Answer:

Question 1

The correct option is  A

Question two

 The correct option is B

Question three

   SE= 0.5  

Question four

   z = - 3

Question five

The correct option is A

Step-by-step explanation:

   The population mean is  \mu =  50 \ grams

   The sample size is  n = 16

   The population size is N  = 4000

   The sample mean is  \= x  =  48.5 \grams

   The standard deviation is s  =  2 \ gram(s)

Considering the first question

 The correct option is  A

z test because the SD of the population is known and the weights follow the normal curve

Considering  the second question

The correct option is  B

Yes, because with only 20 observations the sample SD is not a great estimate of the true population SD.

Considering  the third question  

   Generally the standard error is mathematically represented as

         SE= \frac{s }{\sqrt{n} }

=>      SE= \frac{2 }{\sqrt{16} }

=>       SE= 0.5    

The null hypothesis is  H_o :  \mu  =  50

The alternative  hypothesis is  H_a :  \mu  <  50

Generally the test statistics is mathematically represented as

      z = \frac{ \= x  - \mu  }{ SE }

=>    z = \frac{ 48.5 - 50 }{ 0.5}

=>   z = - 3

Generally the p-value is mathematically represented as

     p-value  = P(Z <  z )

=>  p-value  = P(Z <  - 3  )

From the z-table the

    P(Z <  - 3  ) =0.0013499

=>  p-value  = 0.0013499

From the obtained values we see that

  p-value  <  \alpha

So we reject the null hypotheses

The conclusion

it's very unlikely that the factory is making the candy bars 50 grams as they claim

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Vadim26 [7]

Answer:

9(n + 22) ≤ -15

Step-by-step explanation:

9 times the sum of a number and 22 is at most −15

Let n = number

Times = multiplication

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We must add parenthesis on the end on 22 and before n

We must do this because it says 9 times the sum of a number and 22 which means that 9 is being multiplied by both n and 22

We would have 9(n + 22)

9(n + 22) is at most -15

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Because it says at most 9(n + 22) can equal -15 or anything less than -15

So at most can be replaced with ≤

9(n + 22) ≤ -15

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4 0
3 years ago
I am redesigning a rectangular prism in geometry where I have to minimize the surface area while maintaining the same volume. I
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Strategy:

You will need to make use of the formulas for volume and area of the shapes you have chosen.

... volume of a sphere = (4/3)πr³

... area of a sphere = 4πr²

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___

For your pyramid, it's a bit more complicated. You can use the formula for volume to find a relationship between the side length and the height. Then you can solve for height and put that expression into the equation for surface area. Now, you have an equation for surface area as a function of side length, which you can use to choose side lengths that give surface area in the range you want. You may find a graphing utility to be helpful for this.

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Numbers:

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