36 divided by 6+(18-6x2)

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

5 0

Answer:

12.

Step-by-step explanation:

This equation seems to want you to use the Order of Operations, a.k.a PEMDAS (which stands for Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). When you do a problem like this, you use the Order of Operations to figure out the order in which you'd solve your problem.

You would first solve what is in parentheses, since that is the first letter in PEMDAS. 18-6x2 is what we have in our parentheses, but it's too confusing to be solved yet. The next letter is E, a.k.a exponents, but there are no exponents in this equation, so we move on. Next is M, Multiplication. We would multiply 6 by 2, which gives us 12. Moving on, we have D, Division. We would do 36/6, which is 6.

Our 5th letter is A, Addition. We would have to add our 6 to (18-12), but that couldn't work, since our 18-12 is still in parentheses, and those come first. So, we would skip to the last letter, S, Subtraction. 18-12=6, and since we solved all the problems in the parentheses, we remove them, and add both 6's together, giving us 12.

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what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

So, since the given slope is -3/4, the negative reciprocal is $\frac{4}{3}$ .

We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$