All categories

3 years ago

If a time t was 27 seconds correct to the nearest second, determine:

Mathematics

1 answer:

nalin [4]3 years ago

5 0

answer:

The answer is (b) The upper bound.

Step-by-step explanation:

Sana makatolong

You might be interested in

andrew11 [14]

The answer is. A jeranabo

6 0

3 years ago

The area of a smaller circle is one twenty-fifth of the area of a larger circle. What is the ratio of the radius of the larger c

dangina [55]

Answer:

$f) \: r2 \div r1 \: = 5 \div 1$

Step-by-step explanation:

$\frac{a1}{a2} = \frac{1}{25} = \frac{\pi \times (r1)^{2} }{\pi \times (r2)^{2}}$

${(\frac{r2}{r1})}^{2} = 25$

$\frac{r2}{r1} = 5$

8 0

3 years ago

What is the area of the triangle shown below

mina [271]

Answer:

Step-by-step explanation:

Preliminary

From A, drop a perpendicular to the line BC.

The line BC has to be extended to your right.

Call the intersection point D.

Find angle ABD

ABD and ABC = 180 They are supplementary angles.

140 + ABD = 180

ABD = 40

Find AD

Sin(theta) = AD/AB

AB = 25

Theta = 40

Sin(theta) = AD / 25

Sin(40) = 0.6428

0.6428 = AD / 25 Multiply both sides by 25

AD = 25*0.6428

AD = 16.07

Find the Area of ABC.

The height = 16.07

The base = 40 m

Area = 40*16.07 / 2

Area = 321.4 m^2

6 0

3 years ago

Assume that the number of customers who arrive at a water ice stand follows the Poisson distribution with an average rate of 6.4

Nady [450]

Answer:

18.88% probability that three or four customers will arrive during the next 30 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Average rate of 6.4 per 30 minutes.

This means that $\mu = 6.4$

What is the probability that three or four customers will arrive during the next 30 minutes?

$P = P(X = 3) + P(X = 4)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-6.4}*(6.4)^{3}}{(3)!} = 0.0726$

$P(X = 4) = \frac{e^{-6.4}*(6.4)^{4}}{(4)!} = 0.1162$

$P = P(X = 3) + P(X = 4) = 0.0726 + 0.1162 = 0.1888$

18.88% probability that three or four customers will arrive during the next 30 minutes

4 0

4 years ago

Help me please someone asap! Giving brainiest to CORRECT answers

jeka57 [31]

a. $8.62845 × 10²$

8 0

3 years ago