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Anton [14]
3 years ago
9

How many 2-digit numbers can be formed using only the digits 2, 3, 5 and 6, if the numbers are not repeated within a number?

Mathematics
1 answer:
larisa [96]3 years ago
8 0

(1) Repetition allowed : There are 4 choices for both positions, so 4 × 4 = 16 2-digit numbers can be formed. (2) Repetition not allowed : There are 4 options for tens position, and three options for ones position. Therefore, 4 × 3 = 12 2-digit numbers can be formed.

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Please help<br><br>thank you​
DaniilM [7]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Which number has the GREATEST value? A) 1 /4 B) 22% C) 0.26 D) 1 /5
larisa [96]

The answer would be C) 0.26

6 0
4 years ago
WILL MARK BRAINLIEST WILL REPORT IF U GIVE ME A LINK TO UKNOWN THING
meriva

Answer:

I think the answer will be x⩽4

5 0
3 years ago
In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =
const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}

The expression can be simplified as:

t = 2\sqrt{\frac{h}{16}}

For a player that has a hang time of 0.9s, the jump is found as follows:

0.9 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.9}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2

h = 16\left(\frac{0.9}{2}\right)^2

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

0.8 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.8}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2

h = 16\left(\frac{0.8}{2}\right)^2

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

3 0
2 years ago
What percent of $3.60 is $0.36
Sindrei [870]
\frac{0.36}{3.6} \cdot 100\%= \frac{36}{3.6} \%= \frac{360}{36}\% =10\%
8 0
3 years ago
Read 2 more answers
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