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Naily [24]
3 years ago
10

AB is dilated by a scale factor of 3 to form A1B1. Point O, which lies on AB, is the center of dilation. The slope of AB is 3. T

he slope of A1B1 is . Through point O.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

Slope\ of\ A'B'= 3

Step-by-step explanation:

Given

Slope\ of\ AB= 3

Required

Determine the slope of A'B'

Represent the coordinates of AB with (x,y), such that

AB = (x,y)

Since A'B' is 3 * AB, we have

A'B' = 3 * AB

Substitute (x,y) for AB

A'B' = 3 * (x,y)

A'B' = (3x,3y)

Since the slope of AB = 3, then the slope of A'B' is also equal to 3 because dilation through (0,0) does not have effect on the slope

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<span>Length = 1200, width = 600
   First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as: W = (2400 - L)/2
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    And expand: A = (2400L - L^2)/2 A = 1200L - (1/2)L^2
    Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
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 A = 1200(1200+e) - (1/2)(1200+e)^2
 A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
 A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
 A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
 A = 720000 - (1/2)e^2
   And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
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