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Sergeu [11.5K]
3 years ago
12

Is the relation a function? Yes or No? (4,5),(4,-7), (4,2), (4,0), (4,9)

Mathematics
2 answers:
Iteru [2.4K]3 years ago
4 0

Answer:

No, because 4 is repeated in the domain.

Step-by-step explanation:

Mumz [18]3 years ago
3 0

Answer:

No it's not a function

Step-by-step explanation:

When the domain repeats either once or more, it's never a function

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What is (2/3)^4 <br> does anybody know?
Sveta_85 [38]

Answer:

<h2>16/18</h2>

Step-by-step explanation:

<h2>hopes this helps. Mark as brainlest plz!</h2>
4 0
3 years ago
A rectangle has length x and width x – 3. The area of the rectangle is 10 square meters. Complete the work to find the dimension
Tamiku [17]

Answer:

Step-by-step explanation:

Area of rectangle = Length × Width

The given rectangle has a length if x meters

The width of the triangle is (x-3) meters

The area of the rectangle is given as 10 square meters.

Area if rectangle = x(x-3) = 10

Multiplying each term in the parentheses,

x^2 -3x = 10

x^2 -3x -10 = 0

This is a quadratic equation

We will look for two numbers such that when they are multiplied, it will give us -10x^2 and when they are added, it will give -3x. It becomes

x^2 + 2x - 5x -10 = 0

x(x+2)-5(x+2) =0

( x + 2)(x-5) = 0

x = -2 or x = 5

The length of the rectangle cannot be negative so the length is 5 meters

Widith = x+3 = 5-3 = 2 meters

5 0
4 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
The sum of three consecutive even integers is 36. What is the second integers?
podryga [215]

let the consecutive even integers be 2x , 2x + 2 and 2x + 4

let's solve for values of the integers :

  • 2x + 2x + 2 + 2x + 4 = 36

  • 6x + 6 = 36

  • 6x = 36 - 6

  • x =  \dfrac{30}{6}

  • x = 5

therefore, the consecutive even integers are :

  • 2x = 2  \times 5 = 10

  • 2x + 2 = 10 + 2 = 12

  • 2x + 4 = 10 + 4 = 14

I hope it helped...

7 0
3 years ago
Please Help Very much confuse and I have to turn this in before this evening
Oksana_A [137]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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