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Alex777 [14]
3 years ago
15

Let ƒ(x) = x + 1 and g(x) = 5x. Evaluate the composition (ƒ ∘ g)(–1). Question 2 options: A) (ƒ ∘ g)(–1) = 6 B) (ƒ ∘ g)(–1) = –4

C) (ƒ ∘ g)(–1) = 4 D) (ƒ ∘ g)(–1) = –6
Mathematics
1 answer:
Papessa [141]3 years ago
5 0

Answer:

answer B

Step-by-step explanation:

hello,

f(x)=x+1\\g(x)=5x \ \ so\\(fog)(-1)=f(g(-1))=f(-5)=-5+1=-4

so the winner is the answer B

hope this helps

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Answer:

In the Amazon rainforest, the agouti (a small rodent) and the brazil nut tree are very dependent on each other. The brazil nut tree drops its pods when they ripen, but they would not split open if it were not for the agouti's sharp teeth - the only forest animal which can split the tough pods. The agouti benefits by eating the brazil nuts, but like squirrels, agoutis hide and bury surplus nuts - and many of these take root, thus replenishing stocks of brazil nut trees.

7 0
3 years ago
A number divided by -9 is less than 10
miv72 [106K]
N/(-9) < 10
Hope this helps!
5 0
4 years ago
Olay i fixed it number 2
Leto [7]
U answer it already the picture shows that it already been answer 
6 0
3 years ago
What is the remainder when a^3-4 is divided by a+2?
Harman [31]

Answer:

-12

Step-by-step explanation:

Use synthetic division to find the remainder:

a + 2 yields the synthetic division divisor -2.  The four coefficients of a^3 - 4 are {1, 0, 0, -4}.  Setting up synthetic division results in:

-2   /   1    0    0    -4

              -2    4     -8

     -------------------------

         1     -2    4    -12

The remainder is -12.  This is also the value of a^3 - 4 when a = -2.

     

6 0
3 years ago
What is the equation of the circle with center (0, 1) and a radius of 10?
victus00 [196]

<u>Answer:  </u>

The equation of the circle with center (0, 1) and a radius of 10 is \bold{x^{2} + y^{2} - 2y-99 = 0}

<u>Solution: </u>

Equation of circle whose center (h, k) and radius r is given as,

(x-h)^{2} + (y-k)^{2} = r^{2} ---- eqn 1

From question, given that the circle has radius 10 and center (0, 1). We have to find the equation of the circle.

Hence we get, h = 0 ; k = 1; r = 10

By using eqn 1, the equation of circle whose center (0, 1) and radius 10 is given as

(x-0)^{2} + (y - 1)^{2} = 10^{2}

On Simplifying we get

x^{2} + (y-1)^{2} = 10^{2}

Expand (y-1)^{2} using the formula (a-b)^{2} = a^{2} - 2ab + b^{2}

x^{2} + y^{2} - 2y + 1 = 10^{2}

x^{2} + y^{2} - 2y + 1 = 100

x^{2} + y^{2} - 2y + 1-100 = 0

x^{2} + y^{2}- 2y- 99 = 0

Hence equation of the circle with center (0, 1) and a radius of 10 is  \bold{x^{2}+y^{2}-2 y-99=0}

3 0
4 years ago
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