All categories

3 years ago

Imagine tossing a fair coin 3 times. what is the sample space for this chance proces

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

8 0

A fair coin just means 50% heads 50% tails. so the sample is still 50% heads 50% tails.

You might be interested in

Lois is riding in the country. after riding her bike at a constant speed for 4 hours, she finds that she traveled a distance of

never [62]

She is going 13 miles an hour or 52 divided by 4

7 0

3 years ago

Read 2 more answers

Andrew, Brenda and Cammi all work part-time at a supermarket. Cammi earns $20 more than Andrew

stellarik [79]

Step-by-step explanation:

Let Andrew wage be = X

Cammi earns $20 more than Andrew So Cammi earns = 20 + X

Brenda earns $30 less than twice Andrew's wage

So she earns = 2X - 30

Their total combanied wage is $400

So Andrew + Cammi + Brenda = $400

X + 20+X + 2X-30 =400

4X - 10 =400

4X=400+10

4X=410

X= $102.5

So Andrew earns $102.5

Cammi earns $122.5

Brenda earns $175

4 0

2 years ago

Which polynomial is in standard form? A) 2x + 3x3 + 5x5 + 9x4 + 2x B) 5 + 3x + x2 + 2x4 + 2x5 C) 8x7 + 3x6 + x5 + 5x4 − 2x3 D) 8

sasho [114]

Answer: [C]: " 8x⁷ + 3x⁶ + x⁵ + 5x⁴ − 2x³ " .
__________________________________________________

6 0

3 years ago

Read 2 more answers

9e^x-240=6e^x+270 what is the solution

zmey [24]

e^x=170

because you subtract like terms (or add, it depends) then simplify (im bad at explaining)

4 0

3 years ago

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the only solution to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago