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Morgarella [4.7K]
2 years ago
8

Find the area of a circle whose circumference is the same as the perimeter of a square of side 22 cm. (Take π = 22/7)

Mathematics
2 answers:
ddd [48]2 years ago
7 0

Answer:

176cm²

Step-by-step explanation:

Side of square = 22cm

Perimeter of square = 88cm

Circumference of circle = perimeter of square

2π r = 88cm

2 x 22/7 x r = 88cm

44/7 x r = 88cm

r = 88 x 7/44

r = 14cm

Area of circle = π x r x r

= 22/7 x 14 x 14

= 44 x 4

= 176 cm²

Nadya [2.5K]2 years ago
5 0

Answer:

Perimeter of a square=circumference of circle

4×22=2πr

44=πr

r=14

Area of circle=πr2

22/7×14×14

28×22

616

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If rx - st = r , which expression represents x
expeople1 [14]
Your goal is to have x by itself
Send st to other side
rx= r+st

Divide by r so x stays alone

X=(r+st)/r

Which is also equal to

X=r/r+st/r
X= 1+st/r
5 0
2 years ago
Helppp!!<br> right answers only please!
Savatey [412]

Answer:

Y-intercept

Step-by-step explanation:

The y-intercept is the part of the line that crosses the y-axis.

The red dot (where the arrow is pointing to) is the y intercept

4 0
2 years ago
In this problem,y = 1/(x2 + c)is a one-parameter family of solutions of the first-order DEy' + 2xy2 = 0.Find a solution of the f
trasher [3.6K]

Differentiate the given solution:

y=\dfrac1{x^2+C}\implies y'=-\dfrac{2x}{(x^2+C)^2}

Substitute y and y' into the ODE:

-\dfrac{2x}{(x^2+C)^2}+2x\left(\dfrac1{x^2+C}\right)^2=0

and it's easy to see the left side indeed reduces to 0.

6 0
3 years ago
An unopened cereal box contains `15/28` cubic foot of cereal. If the box is full, and the length and height of the box are `5/7`
babymother [125]

Answer:

A. `1/2` foot

Step-by-step explanation:

The computation of the width of the box is shown below:

15 ÷ 28 = (5 ÷ 7)(1 1 ÷ 2)(width)

15 ÷ 28 = (5 ÷ 7)(3 ÷ 2)width

15 ÷ 28 = (15 ÷ 14)width

(15 ÷ 28) ÷ (15 ÷ 14) = width

(15 ÷ 28) × (14 ÷ 15) = width

w = 14 ÷ 28

= 1 ÷ 2 ft

7 0
3 years ago
Read 2 more answers
the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se
swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

#SPJ1

3 0
2 years ago
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