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sergejj [24]
4 years ago
12

What are three types of evidence that supports sea floor spreading

Chemistry
2 answers:
sergeinik [125]4 years ago
4 0

1. Rocks near mid-ocean ridge were younger than rock near trenches.

2. Matching bands of magnetic rocks were found on either side the mid-ocean ridge; record changes in earth's magnetic field over a period of time.

3. Earthquake data showed oceanic crust is sinking on to the mantle at the trenches.

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</span>
My name is Ann [436]4 years ago
3 0

1. Rocks near mid-ocean ridge were younger than rock near trenches.

2. Matching bands of magnetic rocks were found on either side the mid-ocean ridge; record changes in earth's magnetic field over a period of time.

3. E<span>arthquake data showed oceanic crust is sinking on to the mantle at the trenches.</span>

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Que es la actividad física y en qué mejora
g100num [7]
La actividad física regular puede mejorar su fuerza muscular y aumentar su resistencia. El ejercicio proporciona oxígeno y nutrientes a sus tejidos y ayuda a que su sistema cardiovascular funcione de manera más eficiente. Y cuando la salud de su corazón y pulmones mejoran, tiene más energía para hacer frente a las tareas diarias. Encantado de ayudarle
4 0
3 years ago
How many molecules of he are contained in a 10.0 l tank at 7.53 atm and 485 k?
ankoles [38]

Answer:

1.126 x 10^22

Explanation:

pV = nRT

7.53 x 10 = n x 8.31 x 485

n = (7.53 x 10) / (8.31 x 485) = 0.0187 moles

M = n x Avogadros number

0.0187 x 6.02 x 10^23 = 1.126 x 10^22

4 0
3 years ago
If 175 g of phosphoric acid reacts with 150.0 g of sodium hydroxide, what is the limiting reactant? How many grams of sodium pho
Evgen [1.6K]

Answer:

NaOH is the limiting reactant.

204.9 g of sodium phosphate are formed.

51.94 g of excess reactant will remain.

Explanation:

The reaction that takes place is:

  • H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

First we <u>convert the mass of both reactants to moles</u>, using their <em>respective molar masses</em>:

  • H₃PO₄ ⇒ 175 g ÷ 98 g/mol = 1.78 mol
  • NaOH ⇒ 150 g ÷ 40 g/mol = 3.75 mol

1.78 moles of H₃PO₄ would react completely with (1.78 * 3) 5.34 moles of NaOH. There are not as many NaOH moles so NaOH is the limiting reactant.

--

We <u>calculate the produced moles of Na₃PO₄</u> using the <em>limiting reactant</em>:

  • 3.75 mol NaOH * \frac{1molNa_3PO_4}{3molNaOH} = 1.25 mol Na₃PO₄

Then we <u>convert moles into grams</u>:

  • 1.25 mol Na₃PO₄ * 163.94 g/mol = 204.9 g

--

We calculate how many H₃PO₄ moles would react with 3.75 NaOH moles:

  • 3.75 mol NaOH * \frac{1molH_3PO_4}{3molNaOH} = 1.25 mol H₃PO₄

We substract that amount from the original amount:

  • 1.78 - 1.25 = 0.53 mol H₃PO₄

Finally we <u>convert those remaining moles to grams</u>:

  • 0.53 mol H₃PO₄ * 98 g/mol = 51.94 g
3 0
3 years ago
Which statement about Bohr’s model of the atom is false?
AfilCa [17]

Answer:

Bohr o saka mi ad ha piebald webs ldb

Explanation:

3 0
3 years ago
Read 2 more answers
HELP PLEASE!!! Write the chemical equation and balance it!!!
nirvana33 [79]
You can start by writing out the molecular formula of each molecule.

Aluminum (Al 3+) Phosphate (PO4 3-)

AlPO4

Nickel II (Ni 2+) sulfide (S 2-)

NiS

Aluminum Sulfide

Al2S3

Nickel Phosphate

Ni3(PO4)2

If you’re wondering, we get those charges by looking at the periodic table. The metals usually have a + charge based on their group number. The nonmetals usually - charge egual to 8 - their group number.

You then balance the ions by flipping the charges, dropping the signs, and adding them in as subscripts.

Now we can put it into an equation


AlPO4 + NiS —-> Al2S3 + Ni3(PO4)2

Balance by adding coefficients

2 AlPO4 + 3 NiS —-> Al2S3 + Ni3(PO4)2



8 0
4 years ago
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