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Archy [21]
3 years ago
12

How many molecules of he are contained in a 10.0 l tank at 7.53 atm and 485 k?

Chemistry
1 answer:
ankoles [38]3 years ago
4 0

Answer:

1.126 x 10^22

Explanation:

pV = nRT

7.53 x 10 = n x 8.31 x 485

n = (7.53 x 10) / (8.31 x 485) = 0.0187 moles

M = n x Avogadros number

0.0187 x 6.02 x 10^23 = 1.126 x 10^22

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