The atomic number is the total number of protons in an atom.
Answer: C. 112 grams
Using the law of conservation of mass, you can say that the total mass of the reactant would be equal to total mass of the product. The reactant of this reaction would be 200g CaCO3(calcium carbonate). The product would be x g <span>calcium oxide(CaO) and 88g carbon dioxide(CO2). The calculation would be:
reactant = product
200g= 88g+ x
x= 200g-88g= 112g
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The answer is <span>one liter.
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The volume of the cube (V) is:
V = l · w · h (l - length, w - width, h - height)
It is known:
l = 10 cm
w = 10 cm
h = 10 cm
Therefore:
V = 10 · 10 · 10 = 1000 cm³
1 cm³ is equivalent to 0.001 liter, therefore 1000 cm³ is:
1 cm³ : 0.001 l = 1000 cm³ : x
x = 0.001 l · 1000 cm³ ÷ 1 cm³ = 1 l
Answer:
structure formula C3H5CH3
Answer:
1.8 g
Explanation:
Step 1: Write the balanced equation
CH₃CH₃(g) + 3.5 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(g)
Step 2: Determine the limiting reactant
The theoretical mass ratio of CH₃CH₃ to O₂ is 30.06:112.0 = 0.2684:1.
The experimental mass ratio of CH₃CH₃ to O₂ is 0.60:3.52 = 0.17:1.
Thus, the limiting reactant is CH₃CH₃
Step 3: Calculate the mass of CO₂ produced
The theoretical mass ratio of CH₃CH₃ to O₂ is 30.06:88.02.
0.60 g CH₃CH₃ × 88.02 g CO₂/30.06 g CH₃CH₃ = 1.8 g