<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
80,10,66
Step-by-step explanation:
Hope this helps :)
Answer: C
Triangle=36+42+102=180
Answer:
x4+7x3-2x2-9x-3 remainder -10
or we could write it as
x4+7x3-2x2-9x-3 - 10/(x+8)
Step-by-step explanation:
x+8 ) x5+15x4+54x3−25x2−75x−34 (x4+7x3-2x2-9x-3 <--- Quotient.
x5+ 8x4
7x4+54x3
7x4+56x3
-2x3-25x2
-2x3-16x2
-9x2-75x
-9x2-72x
-3x-34
-3x-24
-10 <--- Remainder.
