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Dovator [93]
3 years ago
8

A kilobyte is 210 bytes and a megabyte is 220 bytes. How many kilobytes are in a megabyte? 2200 kilobytes 230 kilobytes 210 kilo

bytes 2 kilobytes
Mathematics
2 answers:
rjkz [21]3 years ago
6 0
The answer to your question is 220x210=2200 
hope this helps good luck.
yulyashka [42]3 years ago
4 0

Answer:

2 to the 10 power

Step-by-step explanation:

2 to the 20 power divided by 2 to the 10 power.

20-10

10

2 to the 10 power

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HALPPPPPPPPPPPPP<br><br>which choice shows the values from least to greatest?​
KiRa [710]

Answer:

Choice A

Step-by-step explanation:

-88<-75<-71<-51

Mark me brainliest if this helped

3 0
3 years ago
Read 2 more answers
Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

3 0
3 years ago
The relationship between a bacteria population p, in thousands, and time d, in days, since it was measured to be 1,000 can be re
Assoli18 [71]

d = log₂p represents a logarithmic function, The expression log₂(10) tells us when the population reaches 10,000 and the equation 7 = log₂(128) tells us that the population reaches 128,000 in 7 days.

<h3>What is an exponential function?</h3>

An exponential function is in the form:

y = abˣ

Where a is the initial value of y and b is the multiplication factor.

Let p represent the bacteria population in thousand after d days.

Since each day, the bacteria population grows by a factor of 2, hence:

p=2^d

Hence, d = log₂p represents a logarithmic function

The expression log₂(10) tells us when the population reaches 10,000 and the equation 7 = log₂(128) tells us that the population reaches 128,000 in 7 days.

Find out more on exponential function at: brainly.com/question/12940982

8 0
2 years ago
I need help finding the missing angles, please show work
Leno4ka [110]
It's an isosceles triangle, which means base angles are equal.

48 = 6x

48/6 = x

8 = x

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The two missing angles are 48° and 84°.
7 0
3 years ago
Heston wagons reported in June that 20 out of 500 wagons failed inspection. In July they reported that 25 out of 625 wagons fail
elena-14-01-66 [18.8K]

Answer:

The proportion is \frac{y}{x} =\frac{1}{25}

Step-by-step explanation:

We have to:

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On July 25 of 625 wagons failed

If we call x the number of wagons and and the number of wagons that had failures then we have to for June:

\frac{y}{x} = \frac{20}{500}\\\\\frac{y}{x} = \frac{1}{25}

For July we have

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The proportions are the same for both months

\frac{20}{500} = \frac{25}{625}

The proportion is \frac{y}{x} =\frac{1}{25}

This means that of every 25 wagons, one has faults

7 0
3 years ago
Read 2 more answers
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