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atroni [7]
3 years ago
14

The sum of the three angles in a triangle is 180 degrees. One of the angle measures 30 degrees, and the second angle measures 75

degrees. What is the measure of the third triangle?
Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0

Answer: the measure of the third triangle is 75 degrees.

Step-by-step explanation:

Let the measure of the third angle be x degrees.

The sum of the three angles in a triangle is 180 degrees.

One of the angle measures 30 degrees, and the second angle measures 75 degrees. Therefore,

30 + 75 + x = 180

105 + x = 180

Subtracting 105 from the left hand side and the right hand side of the equation, it becomes

x = 180 - 105 = 75 degrees

Molodets [167]3 years ago
4 0

Answer:

75 degrees

Step-by-step explanation:

30 + 75 = 105

180 - 105 = 75

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Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

m\angle RPS=90^\circ                       [Right angle]

(5x+15)^\circ=90^\circ

(5x+15)=90

5x=90-15

5x=75

Divide both sides by 5.

x=\dfrac{75}{5}

x=15

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

m\angle RQP=(2x+3)^\circ

Putting x=15, we get

m\angle RQP=(2(15)+3)^\circ

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and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

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(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

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