You will need human body specific heat, Cp, to do the maths.
In Internet I found this data: Cp = 3470 j / kg * °C
Now transform the power to work, by: P = Work / time => Work = P * time
Work = 1000 W * 39 min * 60 min/ s = 2,340,000 j
We will use T = 37 °C as the initial body temperature.
Now use Heat = m*Cp*ΔT = 70 kg * 3470 j / kg * °C * (T - 37°C) = 2,340,000 j
You can now isolate T = 2340000 / [70*3470] + 37°C = 46.6 °C
Let v = the launch velocity.
Because the launch angle is 40° (with the horizontal), the initial vertical velocity is
v* sin(40°) = 0.6428v m/s.
Assume g = 9.8 m/s² and ignore air resistance.
At maximum height, the vertical velocity is zero.
Because the maximum vertical height is 10 m, therefore
(0.6428v m/s)² - 2*(9.8 m/s²)(10 m) = 0
0.4132v² = 196
v = 21.78 m/s
Answer: 21.8 m/s (nearest tenth)
Answer:
a. 6
b. 6 m/s²
c. 300 m to the right
d. 30 secs
Explanation:
slope = rise /run
60-0/10-0
= 6
b. slope = acceleration = 6 m/s²
c. d=ut+1/2at²
t=10 (segment A last for 10 secs)
u - initial velocity = 0
so d = 0(10)+1/2*6*10²
=300 m
work done=446.9 J . so option (c) is correct.
Explanation:
the formula for work done is given by
W= F d
F= force= mg where m= mass and g= acceleration due to gravity
F= 3.8 (9.8)=37.24 J
so W=37.24 (12)
W=446.9 J
Answer:
Explanation:
In order to solve this problem, we will need to draw a free body diagram of both situations (see attached picture).
So first, we need to find what the mass of the object is. We can do so by analyzing the horizontal movement of the first situation, so we get:
F=ma
so
m=2.34kg
next, we can analyze the second situation, we will start by analizing the vertical movement so we can determine the Normal force, so we get:
N=W
N=mg
N=3.79N
so now we can analyze the horizontal movement of the block, so we get: