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makvit [3.9K]
2 years ago
9

a person using a machine applies a force of 100 newton's over a distance of 10 Meters to raise a 500 n object 1.5 meters what is

the work input?
Physics
1 answer:
Hoochie [10]2 years ago
7 0

Answer:

Work done by the machine (W) =  500 × 1.5 = 750 J

Work supplied to the machine (W) = 100 × 10 = 1000 J

              Here, work supplied to the machine is input work = 1000 J

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<span>The medium in which it travels through</span>
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If a rigid body rotates about a fixed axis passing through its center of mass, the body's linear momentum is
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Answer:

The linear momentum is zero

Explanation:

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Hypothetically speaking, if an object were located at the center of the Earth, the gravitational force on that object due to the
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The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca
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V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}

the elastic potencial energy is given by:

U_e=\frac{1}{2}*k*x^2\\U_e=\frac{1}{2}*1100N/m*(4m)^2\\U_e=8800J

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this work is negative because is opposite to the movement.

The gravitational potencial energy at 2.5 m aboves is given by:

U_{gf}=m*g*h\\U_{gf}=60kg*9.8*2.5\\U_{gf}=1470J

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3 0
3 years ago
The speed of light (c) is:
Radda [10]

Answer:

A

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2 years ago
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