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Mars2501 [29]
3 years ago
8

How is Uranus colder than Neptune

Physics
1 answer:
STatiana [176]3 years ago
4 0
With Uranus at an average distance of 2.88 billion kilometres from the Sun and Neptune at an average distance of 4.5 billion kilometres it would be very easy to point out which of the gas giants is the coldest, but if you were you were to say that Neptune was the coldest, you’d be wrong.<span>Given that we expect planets further from the Sun to be colder than those closer, this does make Neptune and Uranus quite a mysterious pair. Uranus and Neptune are brimming with volatiles such as water, methane and ammonia and due to their composition in comparison to Jupiter and Saturn, which are comprised mainly of hydrogen and helium, are labelled the ice giants. Scientists have measured how hot Uranus and Neptune should be and have found that Uranus is very cold and very dim</span>
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Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
nikdorinn [45]

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

P=60+100\\P=160 [W]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

P=V*I

where:

P = power [W]

V = voltage [V]

I = current [amp]

I = P/V\\I=160/240\\I=0.67 [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

V=I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R

60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

R = 133.66 + 225\\R = 358.67 [ohms]

7 0
3 years ago
Tom rides his motorcycle at a speed of 15 meters/second for an hour.
Dahasolnce [82]

Answer:

1 hour to ride his motorcycle

4 0
3 years ago
Ch 31 HW Exercise 31.10 7 of 15 Constants You want the current amplitude through a inductor with an inductance of 4.90 mH (part
sergey [27]

Answer:

f = 130 Khz

Explanation:

In a circuit driven by a sinusoidal voltage source, there exists a fixed relationship between the amplitudes of the current and the voltage through any circuit element, at any time.

For an inductor, this relationship can be expressed as follows:

VL = IL * XL (1) , which is a generalized form of Ohm's Law.

XL is called the inductive reactance, and is defined as follows:

XL = ω*L = 2*π*f*L, where f is the frequency of the sinusoidal source (in Hz) and  L is the value of the inductance, in H.

Replacing in (1), by the values given of VL, IL, and L, we can solve for f, as follows:

f = VL / 2*π*IL*L = 12 V / 2*π*(3.00*10⁻³) A* (4.9*10⁻³) H = 130 Khz

5 0
3 years ago
Evaporation only occurs at the surface of a liquid
Veseljchak [2.6K]

yes

evaporation starts on the surface

8 0
4 years ago
A student holds a bike wheel and starts it spinning with an initial angular speed of 9.0 rotations per second. The wheel is subj
zloy xaker [14]

Answer:

T = 0.00889 N*m

Explanation:

Given the initial speed

Vo = 9.0rev/s.

V = 65 rev/10s

V = 6.5 rev/s.

V = Vo + a*t

Solve to acceleration knowing the initial velocity and the velocity at 10 s

6.5 rev/s - 9 rev/s = a*10s

a = -0.25 rev/s^2.

Now the solve the time at stop time so V=0

V = Vo + a*t

0 = 9.0 - 0.25 rev/s *t,

t = 36 s The Stopping time.

36s -  10s = 26s

The torque can be find using the acceleration using the equation

T = I*a

I = 1/2*m*r^2

I = 1/2*0.725kg*(0.315m)^2= 0.0359kg*m^2

T = 0.0359kg*m^2*-0.25rev/s^2

T = 0.00889 N*m

7 0
3 years ago
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