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3 years ago

14

A squash ball with an initial velocity of 19.21 m/s [W] is hit by a squash racket, changing its velocity to 40.22 m/s [E] in 0.3

12 s. What is the squash ball’s average acceleration?

1 answer:

alexgriva [62]3 years ago

4 0

Acceleration = (change in velocity) / (time for the change)

Change in velocity = 59.43 m/s East

Time for the change = 0.312 s

Acceleration = 190.5 m/s^2 East

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how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch

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The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

$\rho = \frac{PM}{RT}$

$\frac{dP}{dz} = -\rho g\\\\$

where;

<em>ρ is density</em>
<em>T is temperature</em>
<em>dP is rate of change of vertical pressure</em>

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

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