Will start to distribute the 2 in (x-7)
so it can be (2x-2*7)=100
(2x-14)=100
2x=100+14
2x=114
x=114/2
x=57
The height of the ladders as the Independent variable is the one that I change
Answer?
Step-by-step explanation:
Put x = -2 and y = 5 to the expression.
![\left[3\cdot(-2)^3(5)^{-2}\right]^2=\left[3(-8)\cdot\dfrac{1}{5^2}\right]^2=\left(-24\cdot\dfrac{1}{25}\right)^2=\left(-\dfrac{24}{25}\right)^2\\\\=\dfrac{24^2}{25^2}=\dfrac{576}{625}](https://tex.z-dn.net/?f=%5Cleft%5B3%5Ccdot%28-2%29%5E3%285%29%5E%7B-2%7D%5Cright%5D%5E2%3D%5Cleft%5B3%28-8%29%5Ccdot%5Cdfrac%7B1%7D%7B5%5E2%7D%5Cright%5D%5E2%3D%5Cleft%28-24%5Ccdot%5Cdfrac%7B1%7D%7B25%7D%5Cright%29%5E2%3D%5Cleft%28-%5Cdfrac%7B24%7D%7B25%7D%5Cright%29%5E2%5C%5C%5C%5C%3D%5Cdfrac%7B24%5E2%7D%7B25%5E2%7D%3D%5Cdfrac%7B576%7D%7B625%7D)
explanation
The answer is not infinity.
<span>Consider FBDs of each mass with the direction of motion of m1 as positive </span>
<span>m1*g-T=m1*a </span>
<span>T-m2*g=m2*a </span>
<span>assuming mass less cord and mass less, friction less pulley </span>
<span>the accelerations are equal </span>
<span>a=(T-m2*g)/m2 </span>
<span>m1*g-T=m1*(T-m2*g)/m2 </span>
<span>do some algebra </span>
<span>m1*g-T=m1*T/m2-m1*g </span>
<span>2*m1*g=T*(1+m1/m2) </span>
<span>2*m1*m2*g=T*(m2+m1) </span>
<span>2*m1*m2*g/(m2+m1)=T </span>
<span>now take the limit of T as m1->infinity </span>
<span>T=2*m2*g </span>
<span>this is intuitively correct since the maximum acceleration of m1 is -g, the cord transfers the acceleration to m2, which is being acted on by gravity downward and an upward acceleration of g. Therefore the maximum acceleration of m1 is 2*g upward. </span>
