1.
(Create a table then plot the points)
X | 0 | 1 | 2 | 3 |
-------------------------
Y | -1 | 3 | 7 | 11 |
4 (0) -1 => 0 - 1 = -1
4 (1) -1 => 4 - 1 = 3
4 (2) -1 => 8 - 1 = 7
4 (3) -1 => 12 - 1 = 11
Just apply the table method to the others and you should be fine! :)
Answer:
x = -b +or- the square root of (b^2-4ac) ALL / 2a
sing to "pop goes the weasel" lol
Answer:
The student's current average score will be 69.2
Step-by-step explanation:
Let first test be TEST A: which is 20 of total and secures 62
Let second test be TEST B: which is 20 of the total marks and has secured 83.
Let third test be TEST C: which is 20 of total and has secured 91.
And now the TEST D which is 25 of total and has secured 88.
Therefore, by multipying across
= 12.4
= 16.6
= 18.2
=22
Now, by adding the scores to get the average score
We get, 69.2.
Multiples of 8 are basically the result of counting by 8's. (Technically, multiples are a set of number which can be divided by a certain number without a remainder.)
The first 4 multiples of 8 are {

}.
Your answer for this is 86.49