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3 years ago

6

A jazz concert brought in $167,000 on the sale of 8,100 tickets. If the tickets sold for $15 and $25 each, how many of each type

of ticket were sold?

1 answer:

Phantasy [73]3 years ago

8 0

Answer:

3,550 $15 tixkets and 4,550 $25 tickets were sold.

Step-by-step explanation:

15 × 3550=53250

25 × 4550=113750

53250+113750=167000

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68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se

Mnenie [13.5K]

Answer:

$\boxed{\bf\: The \: park \: sold \boxed{ 34{}} \: child \: tickets.}$

Step-by-step explanation:

<u>Given:</u>

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

<u>To </u><u>Find:</u>

The Number of child tickets the park sold.

<u>Solution:</u>

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

$\sf \: = \: \cfrac{68}{100} \times 50$

<u>Note</u>:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: <u>Cancel One zero of 50 and one zero of 100,That is</u>:-

$\sf = \cfrac{68}{ 10\cancel0} \times 5 \cancel0$

<em>Results to,</em>

$\sf = \cfrac{68}{10} \times 5$

Step 3: <u>Cancel 5 and 10, That is</u>:-

$\sf = \cfrac{68}{ \cancel{10 }} \times \cancel5$

<em>Results to,</em>

$\sf =\: \cfrac{68}{2} \times 1$

$\sf = \cfrac{68}{2}$

Step 4: <u>Cancel 68 and 2, That is</u>:-

$\sf =\: \cfrac{ \cancel{68}}{ \cancel2}$

<em>Results to,</em>

$\sf = \cfrac{34}{1}$

$\sf = 34$

34 is the result.

Hence,

$\underline{ \rm \: The \: park \: sold \: \bold{ 34 } \: child \: tickets.}$

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

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Answer:

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Step-by-step explanation:

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3 years ago

Can someone give me the answers and step by step instructions please??

professor190 [17]

Answer:

$-1,4,-7,10,...$ neither

$192,24,3,\frac{3}{8},...$ geometric progression

$-25,-18,-11,-4,...$ arithmetic progression

Step-by-step explanation:

Given:

sequences: $-1,4,-7,10,...$

$192,24,3,\frac{3}{8},...$

$-25,-18,-11,-4,...$

To find: which of the given sequence forms arithmetic progression, geometric progression or neither of them

Solution:

A sequence forms an arithmetic progression if difference between terms remain same.

A sequence forms a geometric progression if ratio of the consecutive terms is same.

For $-1,4,-7,10,...$ :

$4-(-1)=5\\-7-4=-11\\10-(-7)=17\\So,\,\,4-(-1)\neq -7-4\neq 10-(-7)$

Hence,the given sequence does not form an arithmetic progression.

$\frac{4}{-1}=-4\\\frac{-7}{4}=\frac{-7}{4}\\\frac{10}{-7}=\frac{-10}{7}\\So,\,\,\frac{4}{-1}\neq \frac{-7}{4}\neq \frac{10}{-7}$

Hence,the given sequence does not form a geometric progression.

So, $-1,4,-7,10,...$ is neither an arithmetic progression nor a geometric progression.

For $192,24,3,\frac{3}{8},...$ :

$\frac{24}{192}=\frac{1}{8}\\\frac{3}{24}=\frac{1}{8}\\\frac{\frac{3}{8}}{3}=\frac{1}{8}\\So,\,\,\frac{24}{192}=\frac{3}{24}=\frac{\frac{3}{8}}{3}$

As ratio of the consecutive terms is same, the sequence forms a geometric progression.

For $-25,-18,-11,-4,...$ :

$-18-(-25)=-18+25=7\\-11-(-18)=-11+18=7\\-4-(-11)=-4+11=7\\So,\,\,-18-(-25)=-11-(-18)=-4-(-11)$

As the difference between the consecutive terms is the same, the sequence forms an arithmetic progression.

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